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klemol [59]
3 years ago
15

Abdullah is a quality control expert at a factory that paints car parts. He knows that 20\ , percent of parts have an error in t

heir painting. He recommended a change in the painting process, and he wanted to see if this error rate had changed. He took a random sample of 400400400 parts painted in a month and found that 606060 had an error.
Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0

The error rate has decreased after changing the painting process.

<u>Step-by-step explanation:</u>

Abdulla knows that 20 percent of the parts have an error in their painting. After suggesting changes in painting process, he wants to know whether the error rate has changed.

Number of parts in the random sample=400400400

Number of parts that had an error=606060

We have to determine what percentage of 400400400 is 606060

606060=x/100 \times 400400400\\=0.15%

After changing the painting process 0.15% of parts have error.

The previous percentage was 20.Hence the error rate has clearly changed.

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Please help me!!!!!!!!!!!!!​
monitta

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the following Half-Angle Identities:    tan (A/2) = (sinA)/(1 + cosA)

                                                                     cot (A/2) = (sinA)/(1 - cosA)

Use the Pythagorean Identity: cos²A + sin²B = 1

Use Unit Circle to evaluate: cos 45° = sin 45° = \frac{\sqrt2}{2}

<u>Proof LHS → RHS</u>

Given:                       cot\ (22\frac{1}{2})^o-tan\ (22\frac{1}{2})^o

Rewrite Fraction:     cot\ (\frac{45}{2})^o-tan\ (\frac{45}{2})^o

Half-Angle Identity:   \dfrac{sin(45)^o}{1-cos(45)^o}-\dfrac{sin(45)^o}{1+cos(45)^o}

Substitute:                  \dfrac{\frac{\sqrt2}{2}}{1-\frac{\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{1+\frac{\sqrt2}{2}}

Simplify:                      \dfrac{\frac{\sqrt2}{2}}{\frac{2-\sqrt2}{2}}-\dfrac{\frac{\sqrt2}{2}}{\frac{2+\sqrt2}{2}}

                               =\dfrac{\sqrt2}{2-\sqrt2}-\dfrac{\sqrt2}{2+\sqrt2}

                               =\dfrac{\sqrt2}{2-\sqrt2}\bigg(\dfrac{2+\sqrt2}{2+\sqrt2}\bigg)-\dfrac{\sqrt2}{2+\sqrt2}\bigg(\dfrac{2-\sqrt2}{2-\sqrt2}\bigg)

                               =\dfrac{2\sqrt2+2}{4-2}-\dfrac{2\sqrt2-2}{4-2}

                               =\dfrac{4}{2}

                               = 2

LHS = RHS:  2 = 2  \checkmark

7 0
4 years ago
Yh plss I need an answer to this question plss​
VikaD [51]

Question:

A boy makes a cone of diameter 28 cm without a base. He then cuts a smaller cone of diameter 20 cm from the cone. He used the bottom part as a lampshade. If the height of the lampshade is 11cm,

(a) find the volume of the whole cone.

(b) find in cm2, the area of the material used to make the lampshade.

Answer:

(a) V ≈ 16420.1

(b) A ≈ 2690.1 cm²

Step-by-step explanation:

<u>Solution for (a)</u>

Formula: The formula for the volume of a cone is V = 1/3 hπr².

V= πr² h /3 = π × 28/ 2 × 20/  3 ≈ 16420.0576

16420.0576 in nearest tenths is 16420.1

Therefore, the volume of the whole cone is 16420.1 cm²

<u>Solution for (b)</u>

Formula: A = πrl + πr2.

l = r² + h²

Solving for A

A = πr (r + h²+ r²) = π × 20 × (20 + 112 + 202) ≈ 2690.80077

2690.80077 In nearest tenths, is 2690.1

Therefore, the area of the material used to make the lampshade is 2690.1 cm²

7 0
3 years ago
The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restric
lana66690 [7]
What type of math is this problem? Is it advanced?

6 0
4 years ago
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Ca you answer my screenshot
pentagon [3]

Answer:

= 2\frac{2}{15}

Step-by-step explanation:

3\frac{1}{3} - 1\frac{1}{5}

Convert both fractions to improper fractions

= \frac{10}{3} - \frac{6}{5}

To subtract, find a common denominator of 3 and 5.

= \frac{50 - 18}{15}

= \frac{32}{15}

= 2\frac{2}{15}

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3 years ago
Which of the following terms describes the measure indicated by the black
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Answer:

the answer is A

Step-by-step explanation:

The line is the middle point of the graph/ the middle number of all therefore it's the median.

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2 years ago
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