Answer:
10!
Step-by-step explanation:
You will need to put 2 half cups to make 1.
So, 10 half cups is equal to 5 cups.
a + b ≥ 30, b ≥ a + 10, the system of inequalities could represent the values of a and b
option A
<u>Step-by-step explanation:</u>
Here we have , The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is the greater integer, We need to find which system of inequalities could represent the values of a and b . Let's find out:
Let two numbers be a and b where b>a . Now ,
- The sum of two positive integers, a and b, is at least 30
According to the given statement we have following inequality :
⇒ 
- The difference of the two integers is at least 10
According to the given statement we have following inequality :
⇒ 
⇒ 
⇒ 
Therefore , Correct option is A) a + b ≥ 30, b ≥ a + 10
Answer:
x^2 + 14x + 49 = 0
Step-by-step explanation:
Answer:
–7 is not the arithmetic square root of 49 only in case we are taking it for natural number.
Step-by-step explanation:
- The square root of x is that number which on squaring gives the result as x.
- For example, the square root of 4 is +2 or -2. Because on squaring +2 or -2 we get the number 4.
- Similarly for the case of 49, the square root might be both +7 or -7.
- But if we are taking it as a natural number then -7 is not valid. Like for length, quantity or other sort of things -7 is not the arithmetic square root of 49.
Correct question :
If the perimeters of each shape are equal, which equation can be used to find the value of x? A triangle with base x + 2, height x, and side length x + 4. A rectangle with length of x + 3 and width of one-half x. (x + 4) + x + (x + 2) = one-half x + (x + 3) (x + 2) + x + (x + 4) = 2 (one-half x) + 2 (x + 3) 2 (x) + 2 (x + 2) = 2 (one-half x) + 2 (x + 3) x + (x + 2) + (x + 4) = 2 (x + 3 and one-half)
Answer: (x + 2) + x + (x + 4) = 2 (one-half x) + 2 (x + 3)
Step-by-step explanation:
Given the following :
A triangle with base x + 2, height x, and side length x + 4 - - - -
b = x + 2 ; a = x ; c = x + 4
Perimeter (P) of a triangle :
P = a + b + c
P =( x + 2) + x + (x + 4) - - - (1)
A rectangle with length of x + 3 and width of one-half x
l = x + 3 ; w = 1/2 x
Perimeter of a rectangle (P) = 2(l+w)
P = 2(x+3) + 2(1/2x)
If perimeter of each same are the same ; then;
(1) = (2)
(x + 2) + x + (x + 4) = 2(x+3) + 2(1/2x)
