<u>Part A</u>
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and 
<u>Part B</u>
Diagonals of a parallelogram bisect each other, so

Solving by substitution,

Multiplying both sides by 3,

So, 
<u>Part C</u>
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For x^2-49
this is a diffarence of two perfect squares. I suggest that this is memorised.
a^2-b^2=(a-b)(a+b)
so x^2-7^2=(x-7)(x+7)
so to solve x^2+x-56 you want to find out what two numbers add to 1 and multiply to make -56
since -56 is negative we know that the two number are difarent signs so that eliminatess answers B and D.
if we try answer C -8+7=-1 so the answer is not C because we want +1 not -1
then we see that 8+(-7)=1 so the answer is A
If A and B are independent, then P(A and B) = P(A) * P(B).
Then the probability that A occurs given that B occurs, for example, reduces to the probability that A occurs by itself:

So all you need to do is check that P(A|B) = P(A). If so, then A and B are independent. This is true only for the second case.
Answer:
D. 95 + 47 + 5.12 12 ÷ 4 ≠ 4 ÷ 12.
Step-by-step explanation:
(70 +30) + 72 B. 21 + (-14) + (-53) O C. 67 +1 - 18. So 12÷4≠4÷1/4 + 3/4 + 2. C. 20 + 80 + (-11)
Subtract each number from 190 and then you have all of your answers