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3 years ago

10

PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

1 answer:

Alecsey [184]3 years ago

3 0

Answer:

x= 56 degree

Step-by-step explanation:

sin x= opposite/ hypotenuse

sin x= 66/79

sin x=0.84

sin-1(0.84)= x

x= 56 degree

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The leaning tower of Pisa currently "leans" at a 4 degree angle and has a vertical height of 55.86 meters. How tall was the lean

Marizza181 [45]

Answer:

56 meters.

Step-by-step explanation:

Please find the attachment.

Let the leaning tower's be h meters tall, when it was originally built.

We can see from our attachment that the side with length 55.86 meters is hypotenuse and h is adjacent side for 4 degree angle.

Since we know that cosine relates the adjacent and hypotenuse of a right triangle.

$\text{Cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}$

Upon substituting our given values we will get,

$\text{Cos (4)}=\frac{55.86}{h}$

$h=\frac{55.86}{\text{Cos (4)}}$

$h=\frac{55.86}{0.99756405026}$

$h=55.996\approx 56$

Therefore, the leaning tower was approximately 56 meters, when it was originally built.

6 0

3 years ago

Solve for X<br> A) 13<br> B) 5<br> C) 14<br> D) 1

Drupady [299]

Answer:

B) 5

Circle is 360 degr. So (21x+9) +(23x-5) +(26x+6)=360

Combine like terms 70x+10=360

Additive inverse -10 from both sides, 70x= 350

Divide both side by 70 division Property of Equality x=5.

Check your answer by substituting 5 back into original solution!

Step-by-step explanation:

3 0

3 years ago

Where is the point ( -5, 6 ) located in the coordinate plane <br> ILL make you bainlist

alexira [117]

On the x - axis go to the left five then up 6

5 0

3 years ago

Read 2 more answers

A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha

netineya [11]

Answer:

$(a)\ Area = 195\pi$

$(b)\ Volume = 700\pi$

Step-by-step explanation:

Given

$h = 12$

$d_1 = 10$ --- lower diameter

$d_2 = 20$ --- upper diameter

Solving (a): The curved surface area

This is calculated as:

$Area = \pi l(r_1 + r_2)$

Where

$r_1 = 0.5 * d_1 = 0.5 * 10 = 5$ --- lower radius

$r_2 = 0.5 * d_2 = 0.5 * 20 = 10$ --- upper radius

And

$l = \sqrt{h^2 + (r_1 - r_2)^2$ ---- l represents the slant height of the frustrum

$l = \sqrt{12^2 + (5 - 10)^2$

$l = \sqrt{12^2 + (-5)^2$

$l = \sqrt{144 + 25$

$l = \sqrt{169$

$l = 13$

So, we have:

$Area = \pi l(r_1 + r_2)$

$Area = \pi * 13(5 + 10)$

$Area = \pi * 13(15)$

$Area = 195\pi$

Solving (b): The volume

This is calculated as:

$Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))$

This gives:

$Volume = \frac{1}{3}\pi * 12 * (5^2 + 10^2 + (5 * 10))$

$Volume = \frac{1}{3}\pi * 12 * (25 + 100 + (50))$

$Volume = \frac{1}{3}\pi * 12 * (175)$

$Volume = \pi *4 * 175$

$Volume = 700\pi$

6 0

2 years ago

Y=(‑4)*cos(20+3*π/4)

Crazy boy [7]

Answer:

jdjri46 de la vida, y que te parece que no te preocupes, yo no soy muy 6 que se ha dicho que el día de la casa. la primera vez que se le ve 8fifuifiigig que se ha dicho. 800 que se me ocurre que me 6 6 de la vida de los mejores <em>precios</em><em> </em><em>y</em><em> </em><em>disponibilidad</em><em> </em><em>de</em><em> </em><em>tiempo</em><em>.</em><em> </em><em>el</em><em> </em><em>que</em><em> </em><em>se</em><em> </em><em>le</em><em> </em><em>va</em><em> </em><em>a</em><em> </em><em>ser</em><em> </em><em>la</em><em> </em><em>mejor</em><em> </em><em>manera</em><em> </em><em>de</em><em> </em><em>que</em><em> </em><em>el</em><em> </em><em>juego</em><em> </em><em>de</em><em> </em><em>la</em><em> </em><em>casa</em><em> </em><em>de</em><em> </em><em>papel</em><em>,</em><em> </em>

4 0

3 years ago