Question

PLEASE HELP ME ASAP!!!!

Answer 1

Part A

$\overline{AC}$ and $\overline{BD}$

Part B

Diagonals of a parallelogram bisect each other, so

$BE=ED \implies 2x+3=3y-4 \implies 3y=2x+7 \implies y=\frac{2}{3}x+\frac{7}{3}\\\\AE=EC \implies y+4=4x-6 \implies y=4x-10$

Solving by substitution,

$\frac{2}{3}x+\frac{7}{3}=4x-10$

Multiplying both sides by 3,

$2x+7=12x-30\\\\37=10x\\\\x=3.7$

So, $y=\frac{2}{3}\left(\frac{37}{10} \right)+\frac{7}{3}=\frac{24}{5}$

Part C

$BE=ED=2(3.7)+3=10.4\\\\AE=EC=4(3.7)-6=8.8$

$\therefore BD=2(10.4)=20.8, AC=2(8.8)=17.6$