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3 years ago

7

What is the value of the expression? Y=6 z=2

2 answers:

Crank3 years ago

6 0

Answer:16

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slava [35]3 years ago

4 0

The answer is 16 can u give me brainliest hehehe

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PLEASE HELP ASAP!!

andriy [413]

If I did this correctly it simplifies to 0 = 8. So I think B is the correct answer. Hope this helps!!

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3 years ago

A triangle has a base length given by the equation b = 2x + 4 and a height given by the equation h

Anna11 [10]

It’s 230 I hope this helps

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3 years ago

Find the area of the parallelogram. The figure is not drawn to scale.

valina [46]

Answer:

1330 in.

Step-by-step explanation:

38 x 35 = 1330

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3 years ago

Read 2 more answers

8 x 10^-3 is how many times as great as 4 x 10^-6

mamaluj [8]

For this case we can rewrite the expressions as:

$3 * 10 ^ {- 3} = 0.003$

That is, we run the decimal three times to the left.

$4 * 10 ^ {- 6} = 0.000004$

That is, we run the decimal six times to the left.

So:

$0.003-0.000004 = 0.002996$

So, we have that $3 * 10 ^ {- 3}$ is 0.002996 times bigger than $4 * 10 ^ {- 6}$

Answer:

$3 * 10 ^ {- 3}$ is 0.002996 times bigger than $4 * 10 ^ {- 6}$

7 0

3 years ago

Read 2 more answers

Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval [0,π].

Troyanec [42]

Answer:

Arc length $=\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

Arc length $=9.75053$

Step-by-step explanation:

The arc length of the curve is given by $\int_a^b \sqrt{1+[f'(x)]^2}\ dx$

Here, $f(x)=\int_0^{4.5x}sin(t) \ dt$ interval $[0, \pi]$

Now, $f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( -cos(4.5x)+1 \right )$

$f'(x)=4.5sin(4.5x)$

Now, the arc length is $\int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx$

$\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

After solving, Arc length $=9.75053$

5 0

3 years ago