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Kazeer [188]
3 years ago
8

What is 956.074054898 rounded to the nearest whole number​

Mathematics
1 answer:
Aleks [24]3 years ago
3 0
956 dude this is not difficult
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Plz help will mark brainliest
Vikki [24]

Answer:

I can't see the whole question.

5 0
2 years ago
Simplify without the absolute value |x+3| ; if x>2
inna [77]

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

|3|=3

|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

When is x+3 positive or zero? [greater than or equal to 0]

x+3\ge 0

Subtract 3 on both sides

x\ge -3

*|x+3|=-(x+3) if x+3 is negative or zero.

When is x+3 negative or zero? [less or equal to 0]

x+3\le 0

Subtract 3 on both sides

x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

8 0
2 years ago
Please help me I need help please​
MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

x^2+(p-3)y^2-4x+6y-16=0

<u>Standard equation of a circle:</u>

(x-a)^2+(y-b)^2=r^2

(where (a,b) is the centre of the circle, and r is the radius)

If you expand this equation, you will see that the coefficient of y^2 is always one.

Therefore, p-3=1

\implies p=1+3=4

<u>Additional information</u>

To rewrite the given equation in the standard form:

\implies x^2+y^2-4x+6y-16=0

\implies x^2-4x+y^2+6y=16

\implies (x-2)^2-4+(y+3)^2-9=16

\implies (x-2)^2+(y+3)^2=16+4+9

\implies (x-2)^2+(y+3)^2=29

So this is a circle with centre (2, -3) and radius √29

3 0
2 years ago
Solve for the value of x:-<br> <img src="https://tex.z-dn.net/?f=4x-5%20%3D%203" id="TexFormula1" title="4x-5 = 3" alt="4x-5 = 3
enot [183]

4x-5 = 3

4x = 8

x = 8÷4

x = 2

5 0
2 years ago
Read 2 more answers
An athlete took forward and backward steps of equal distance to warm up before his race. After taking 10 steps total, he was bac
snow_tiger [21]
If he took 5 steps forward and then 5 steps backwards he would be at his starting position
8 0
3 years ago
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