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UkoKoshka [18]
3 years ago
6

How many times does 9 go int 67

Mathematics
2 answers:
Maslowich3 years ago
7 0
The answer should probably be 7.4 with a line over the four, because that is how you show the number is repeating. If you divide 67 and 9 together, you answer would be 7.44444444444444 or something like that. So you cut it down to 7.4 repeating. TRUST ME! 67 divided by 7 would be something like 9.57142857143
Although, 67 divided by 7.4 repeating would be a perfect 9!
AnnZ [28]3 years ago
4 0


°° Awesome question!

I'll show you how to solve this kind of question:

First, you can multiply 9 times any number to see if it's smaller than 67. If it is, it is OK to keep multiplying 9 by more numbers. Let's try this!

9 × 1 obviously equals 9, so we can keep going up.

9 × 2 = 18. Not quite there yet!

Sometimes it is OK for you to skip some numbers, Watch:

9 × 5 = 45. We can keep going. At this point you don't need to go backwards and do 9 × 3 or 9 × 4, because the products will only get farther away from 67.

9 × 6 = 54. We're getting closer!

Let's try to skip one number:

9 × 8 = 72 - HOLD UP! Oh no! We went over a little too much!

Let's try a number in between 6 and 8 - That would be 7, right?

9 × 7 = 63 - We were right on point! Obviously you can't multiply 9 by 8 again because you would get a bigger number - the 72.

__________________________________________________________

That was just one way to go about it, but there's another way, too!

You can divide 9 by 67 and see what you get. You may have a remainder, but you can just throw that out the window when we're all done:

9 ÷ 67 = 7.4444444444444444 The 4 just repeats on and on again, and we don't want that. So just throw those 4's out the window so you're left with 7.

Based on all this work, 9 goes into 67 7 times.

↑   ↑   ↑  Hope this helps! :D

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SOD CAD TOA,


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Here we have the adjacent side = 100, opposite side = 1058. The tower would fall over if it weren't vertical, and we assume the area is flat and level. So tangent of the answer is 10.58.


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