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liubo4ka [24]
3 years ago
12

List three ways express 3 to the 5 power as a product of powers

Mathematics
2 answers:
mel-nik [20]3 years ago
8 0

3^3 × 3^2 = 3^5

3^4 × 3^1 = 3^5

3^2 × 3^3 = 3^5

sweet [91]3 years ago
6 0
3^5 = 3^3 \times 3^2\\\\3^5 = 3^4\times 3^1\\\\3^5 = 9^2 \times 3^1\\\\3^5=3^2\times 27^1

You can chose any three out of those four.

Hope that helped :)
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Jesse added two more numbers to his expression, but the sum did not change. What could the two new numbers be? Explain why the n
kenny6666 [7]

Answer:

0 and 0

Step-by-step explanation:

The only number that can be applied to the expression without changing the sum is 0, for example 5 + 10 = 15, adding 2 0's will be 0 + 5 + 10 + 0 = 15 :D

4 0
3 years ago
Read 2 more answers
Round each decimal number to the near estas integer: 11.90, 5.49, 7.09, 8.5, -2.2
astraxan [27]

11.90 rounds up to 12, which is the nearest integer.

5.49 rounds down to 5.

7.09 rounds down to 7.

8.5 rounds up to 9.

-2.2 rounds down to -2.

8 0
3 years ago
Evaluate: 5-3[2+(-5)]2-8
trasher [3.6K]

Answer:

15

Step-by-step explanation:

5 - 3[ 2 + (-5)] 2 - 8

Subtract 5 from 2 to get −3.

5 - 3 (-3) × 2 - 8

Multiply 3 and −3 to get −9.

5 - (-9 × 2) - 8

Multiply −9 and 2 to get −18.

5 - (-18) - 8

The opposite of −18 is 18.

5 + 18 - 8

Add 5 and 18 to get 23.

23 - 8

Subtract 8 from 23 to get 15.

15

Hope it helps and have a great day! =D

~sunshine~

7 0
2 years ago
Read 2 more answers
(05.06)Which interval on the graph could be described as linear constant?
Yakvenalex [24]
Segment A is a linear constant.  In general a linear constant will be y=k for a horizontal line or x=k for a vertical line.
8 0
3 years ago
Read 2 more answers
Question 3 of 10
MrMuchimi

Answer:

The point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

Step-by-step explanation:

We know the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

Given

The slope m = 4

From the graph, we can take the point (-3, -4)

So, in our case:

(x₁, y₁) = (-3, -4)

m = 4

now substituting m = 4 and (x₁, y₁) = (-3, -4) in the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

y - (-4) = 4(x - (-3))

y + 4 = 4(x+3)

Therefore, the point-slope form  of the line is:

y + 4 = 4(x+3)

Hence, option B is correct.

  • The graph of the line is also attached.

6 0
3 years ago
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