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Usimov [2.4K]
3 years ago
12

What is the equation of the following line written in slope intercept form? (-5,-1)

Mathematics
1 answer:
solmaris [256]3 years ago
4 0

Answer:

\large\boxed{y=-\dfrac{2}{3}x-\dfrac{13}{3}}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

From the graph we have two points (-5, -1) and (-2, -3).

<em>Look at the picture</em>.

Calculate the slope:

m=\dfrac{-3-(-1)}{-2-(-5)}=\dfrac{-2}{3}=-\dfrac{2}{3}

Put it to the equation in slope-intercept form:

y=-\dfrac{2}{3}x+b

We can't read the y-intercept from the graph. Therefore put the coordinates of the point (-5, -1) to the equation and calculate <em>b</em>:

-1=-\dfrac{2}{3}(-5)+b

-1=\dfrac{10}{3}+b         <em>subtract 10/3 from both sides</em>

-\dfrac{3}{3}-\dfrac{10}{3}=b\to b=-\dfrac{13}{3}

Finally:

y=-\dfrac{2}{3}x-\dfrac{13}{3}

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