Answer:
37/5
Step-by-step explanation:
Call the smaller of the two odds = n
Call the next number in the sequence = n + 2
n*(n +2) = 782 Remove the brackets.
n^2 + 2n = 782 Subract 782 from both sides.
n^2 + 2n - 782 = 0 We are going to have to factor this.
Discussion
This problem can't be done the way it is written. The product of an odd integer with another odd integer is and odd integer. There are no exceptions to this. So you need to give a number that has two factors very near it's square root for this question to work.
For example, you could use 783, (which factors) instead of 782 .
Solve
n^2 + 2n - 783 = 0
(n + 29)(x - 27) = 0
<u>Solution One</u>
n - 27 = 0
n = 27
The two odd consecutive integers are 27 and 29.
<u>Solution Two</u>
n + 29 = 0
n = - 29
The two solution integers are -29 and - 27 Notice that - 29 is smaller than - 27.
Answer:
Step-by-step explanation:
Number of the bags = between 8 and 15 and
-
1/2 of bags contain money
- 1/6 of bags contain candy
- 1/3 of bags contain a toy
As per above the number is divisible by 2, 3 and 6. LCM of the three numbers is 6.
<u>
The number between 8 and 15 and divisible by 6:</u>
So the number of bags is 12
Answer:
Step-by-step explanation:
1)=-2
2)=18
3)=2.5
So first of all you would add the two together
so it would be m23.
138÷23 would equal 6,
therefore m would equal six
to check it substitute m for 6 and you should get 138!
