First you calculate the area of the big rectangle (ignoring the small one the bottom):
A1 = 10 x 6 = 60.
next you calculate the small one:
A2 = 2 x 2 = 4
Now you subtract the small one from the big one and you get:
Area of the figure = A1 - A2 = 60 - 4 = 56
There are 2 order pairs there (6,-4),(-2,4)
find the midpoint using the formula
(x1+x2)/2 , (y1+y2)/2
x=6 and -2
y=-4 and 4
(6+2)/2 , (-4+4)/2
8/2 ,0/2
the midpoint is (4,0) A
Answer:
552
Step-by-step explanation:
Answer:
6580cm
Step-by-step explanation:
The answer is 6580cm because....
- Step one First let's figure out what the smaller shape's volume is. To do so we need to multiply ( LxWxH ) so 6x5x? it does not list what the height is so we know it has the same height as the larger shape and it's height is 14cm so we will use 14cm. 6x5x14=420cm
- Step two Now lets find the Volume of the larger shape. So lets do LxWxH so Lx?x14 it does not give us the length so we need to add up all of the numbers along the line. We got 7cm then 5 from the bottom of the smaller shape and 10cm. all ads up to 22cm so 20x22x14=6160
- Finally we add up the following shapes Volume which are 6160+420=6580cm