Consider the thioformaldehyde molecule.
1 answer:
Answer:
In thioformaldehyde molecule,
Central atom - C
lone pairs on central atom - zero
Ideal bond angle between the carbon -hydrogen bonds -
Compared to the ideal angle, you would expect the actual angle between the carbon-hydrogen bonds to be .
Explanation:
The structure of thioformaldehyde is as follows. (in attachment).
From the structure,
Central atom - C
There is no lone pairs are present on the carbon atom, Hence,lone pairs on central atom - zero
The geometry of thioformaldehyde is Trigonal planar.
Hence, the ideal bond angle is .
Ideal bond angle between the carbon -hydrogen bonds -
All bonds in the thioformaldehyde is similar. Therefore,actual angle between the carbon-hydrogen to be .
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Answer:
Here's how I would do it.
Explanation:
A Lewis structure shows the valence electrons surrounding the atoms.
1. Identify the central atoms
The central atoms are the least electronegative atoms (C).
I chose as my central atoms a chain of four C atoms: C-C-C-C
I stuck the most electronegative atom (O) at the end of the chain:
C-C-C-C-O
2. Complete the structure
The hydrogen atoms must be terminal. Add enough to give every atom an octet.
You should get a structure like the one below
Answer:
ΔS = +541.3Jmol⁻¹K⁻¹
Explanation:
Given parameters:
Standard Entropy of Fe₂O₃ = 90Jmol⁻¹K⁻¹
Standard Entropy of C = 5.7Jmol⁻¹K⁻¹
Standard Entropy of Fe = 27.2Jmol⁻¹K⁻¹
Standard Entropy of CO = 198Jmol⁻¹K⁻¹
To find the entropy change of the reaction, we first write a balanced reaction equation:
Fe₂O₃ + 3C → 2Fe + 3CO
To calculate the entropy change of the reaction we simply use the equation below:
ΔS = ∑S - ∑S
Therefore:
ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1
ΔS = +541.3Jmol⁻¹K⁻¹