1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brums [2.3K]
4 years ago
14

Calculate the mass of each sample.

Chemistry
1 answer:
Vsevolod [243]4 years ago
8 0
1 mole of any substance has Avagadro number of molecules and it's weight is equal to its molecular weight.
.......................................................................................................................
Answer 1:
Molecular weight of HNO3 = 63.01 g/mol

Therefore, 1mole of HNO3 = 63.03 g
Hence, 15.7 mole of HNO3 = 63.03 X 15.7
                                            = 989.57 g

Thus, mass of 15.7 mole of HNO3 = 989.57 g
..........................................................................................................................
Answer 2: 
Molecular weight of H2O2 = 34.01 g/mol

Therefore, 1mole of H2O2  = 34.01g
Hence, 0.00104 mole of H2O2  = 34.01 X 0.00104
                                            = 0.03537 g

Thus, mass of 0.00104 mole of H2O2 is 0.03537 g
.........................................................................................................................
Answer 3: 
Molecular weight of SO2 = 64.07 g/mol

Therefore, 1mole of SO2 = 64.07 g
Hence, 72.1  mmole of SO2 = 64.07 X 0.0721
                                            = 4.619 g

Thus, mass of 72.1 mm of SO2 is 4.619 g
.........................................................................................................................
Answer 4:
Molecular weight of XeF2 = 169.29 g/mol

Therefore, 1mole of XeF2 = 169.29 g
Hence, 1.23 mole of XeF2 = 169.29 X 1.23
                                            = 208.23 g

Thus, mass of 1.23 mole of XeF2 is 208.23 g

You might be interested in
What process takes place before an article is published in a scientific journal/
Goshia [24]
Before an article is published in a scientific journal or in any "peer-reviewed" journal the article is reviewed thoroughly by scholars from the journal as well as peers or scholars of the articles author from the same field. This process occurs to provide credibility to the ideas being published and so that readers and other scholars can rely on the validity of the material being published. 
7 0
3 years ago
Which choice is an abiotic factor of an ecosystem?
kumpel [21]

A.Rocks

Because they are not living things

4 0
3 years ago
Read 2 more answers
What is the molecular formula of a compound if its empirical formula is NO2 and its molar mass is 138.02 g/mole?
pogonyaev
Let (NO2)n be the molecular formula,
(14+16x2)n=138.02
n=3
molecular formula: (NO2)3=N3O6
4 0
3 years ago
Read 2 more answers
The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular fo
maw [93]

Answer:

subscript of C in molecular formula = n  subscript of C in empirical formula

Explanation:

5 0
4 years ago
Read 2 more answers
Identify the species that is oxidized and the species that is reduced in this reaction. Also, identify the oxidizing agent and t
natulia [17]

Answer:

Given the equation of the reaction below:

3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)

The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.

Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.

Note: the question is incomplete. a related question is given as follows; Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron transfer reaction. 3Cl2 + 2Al → 6Cl - + 2Al3+ species oxidized:

Explanation:

An oxidation is a process in which there is a loss of electrons whereas  reduction is a process involving the gain of electrons. A redox reaction is a reaction in which oxidation and reduction processes occur concurrently and to the same extent.

In a redox reaction reaction, the substance which is oxidized serves as the reducing agent by donating electrons to the substance which is reduced. On the other hand, the substance which is reduced serves as the oxidizing agent by accepting the electrons donated by the substance which is oxidized. In oxidation, the oxidation number of the substance oxidized increases, whereas in reduction, the oxidation number of the substance decreases.

For example, given the equation of the reaction below:

3Cl₂(g) + 2Al(s) → 6Cl⁻(aq) + 2Al³⁺(aq)

The oxidized species is aluminum, Al, as its oxidation number increases from zero to +3. Al therefore, acts as the reducing agent.

Also, the reduced species is chlorine gas, Cl₂, as its oxidation number decreases from zero to -1. Therefore, Cl, is the reducing agent.

6 0
3 years ago
Other questions:
  • Gases form bubbles in lava. True or false
    15·2 answers
  • Draw the conjugate bases of pyrrole and cyclopentadiene. For pyrrole, please include the N lone pairs. Conjugate Base of Pyrrole
    15·1 answer
  • Help PLEASE HELP PLEASE
    7·1 answer
  • To do an experiment with the peptide H-A-P-P-Y you need to make two buffers. One where the peptide has a net negative charge (Bu
    10·1 answer
  • When the following equation is balanced with lowest whole-number coefficients, what is the coefficient for NO(g)? ___NH3(g) + __
    9·1 answer
  • Can you please help me?
    9·1 answer
  • Help plsssssss... 3C(s) + 2Fe2O3 (5) ► Fe
    15·2 answers
  • What is the total number of atoms in 3.0 grams sample of neon?
    12·1 answer
  • How many moles of carbon dioxide are produced when 5.12 moles of glucose undergoes a combustion reaction?
    5·1 answer
  • Cool air can hold less water vapor than warm air. Apply this fact to explain why clouds and precipitation form on the windward s
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!