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Brums [2.3K]
3 years ago
14

Calculate the mass of each sample.

Chemistry
1 answer:
Vsevolod [243]3 years ago
8 0
1 mole of any substance has Avagadro number of molecules and it's weight is equal to its molecular weight.
.......................................................................................................................
Answer 1:
Molecular weight of HNO3 = 63.01 g/mol

Therefore, 1mole of HNO3 = 63.03 g
Hence, 15.7 mole of HNO3 = 63.03 X 15.7
                                            = 989.57 g

Thus, mass of 15.7 mole of HNO3 = 989.57 g
..........................................................................................................................
Answer 2: 
Molecular weight of H2O2 = 34.01 g/mol

Therefore, 1mole of H2O2  = 34.01g
Hence, 0.00104 mole of H2O2  = 34.01 X 0.00104
                                            = 0.03537 g

Thus, mass of 0.00104 mole of H2O2 is 0.03537 g
.........................................................................................................................
Answer 3: 
Molecular weight of SO2 = 64.07 g/mol

Therefore, 1mole of SO2 = 64.07 g
Hence, 72.1  mmole of SO2 = 64.07 X 0.0721
                                            = 4.619 g

Thus, mass of 72.1 mm of SO2 is 4.619 g
.........................................................................................................................
Answer 4:
Molecular weight of XeF2 = 169.29 g/mol

Therefore, 1mole of XeF2 = 169.29 g
Hence, 1.23 mole of XeF2 = 169.29 X 1.23
                                            = 208.23 g

Thus, mass of 1.23 mole of XeF2 is 208.23 g

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In the article "A Sea of Garbage" what message is each cartoon trying to convey to readers? Do they succeed?
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Answer:

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3 years ago
At the end of the last lesson, you learned there was not enough carbon dioxide in the biodome air, which led to a decrease in en
lakkis [162]

There may be too many plants present or too few animals in the biodome hence the decrease in carbon dioxide .

<h3>What is a biodome?</h3>

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If there is less carbon dioxide in the biodome then it means that there are too many plants present or too few animals in the biodome.

Learn more about ecosystem: brainly.com/question/1673533

4 0
2 years ago
What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i
UNO [17]

Answer:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)

The net equation is then:

Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-

Actual cathode half-equation:

Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)

Actual net reaction:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

6 0
3 years ago
Under what conditions are two atoms different isotopes of the same element
Aloiza [94]
<span>the number of neutrons they have</span>
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3 years ago
1. Consider the decomposition reaction of sodium chlorate. There are 100 grams of
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A. NaCl(s) and O2(g)

B. 2NaClO3(s) —> 2NaCl(s) + 3O2(g)

C. moles NaClO3 = 100 g / 106.44 g/mol = 0.939 mol NaClO3

D. 0.939 mol NaCl (because the NaClO3 and NaCl are in a 1 to 1 ratio)

E. grams NaCl = 0.939 mol • 58.44 g/mol = 54.9 g NaCl

F. moles of O2 = 0.939 mol NaClO3 • (3 mol O2 / 2 mol NaClO3) = 1.41 mol O2

G. grams of O2 = 1.41 mol • 32 g/mol = 45.1 g O2

H. Percent yield = 10/45.1 • 100% = 22.2% yield
6 0
3 years ago
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