By applying Dalton's law of pressure equations we can calculate the total pressure of a mixture of gases by adding together the partial pressures of the component gases
Explanation:
Dalton's law of partial pressure is the concept used in calculating either partial pressure or total pressure in a given mixture of gases.
The law says that each gas has its own pressure which it puts on the mixture of gases. This pressure is called partial pressure. Also, the sum total of all the gases exerting pressure on the mixture is termed total pressure.
The quantity of individual gas can be known and hence it will get easy to calculate its partial pressure.
The relation used is:
Partial pressure = mole fraction of the one gas from mixture x total pressure in the mixture.
It also says that total pressure is equal to:
total pressure = p1 +p2+p3....pn
here p1, p2 is partial pressure of one of gases in mixture.
I think the answer is 1.31m
hope this helps :)
D should be the correct answer. isotopes are atoms that have the same atomic number (number of protons) but different atomic masses (number of protons and neutrons). isotopes also have the same number of electrons since atoms need to have equal numbers of protons and electrons to not be considered ions. Since the number of protons determines the chemical properties of the atom, we can say that all isotopes have the same chemical properties due to the fact that all isotopes have the same atomic number.
I hope this helps. Let me know in the comments if anything is unclear.
Answer:
pH of the final solution = 9.15
Explanation:
Equation of the reaction: HCl + NH₃ ----> NH₄Cl
Number of moles of NH₃ = molarity * volume (L)
= 0.4 M * (300/1000) * 1 L = 0.12 moles
Number of moles of HCl = molarity * volume (L)
= 0.3 M * (175/1000) * 1 L = 0.0525 moles
Since all he acid is used up in the reaction, number of moles of acid used up equals number of moles of NH₄Cl produced
Number moles of NH₄Cl produced = 0.0525 moles
Number of moles of base left unreacted = 0.12 - 0.0525 = 0.0675
pOH = pKb + log([salt]/[base])
pKb = -logKb
pOH = -log (1.8 * 10⁻⁵) + log (0.0525/0.06755)
pOh = 4.744 + 0.109
pOH = 4.853
pH = 14 - pOH
pH = 14 - 4.853
pH = 9.15
Therefore, pH of the final solution = 9.15
