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-Dominant- [34]
3 years ago
5

Which degree of rotation is equivalent to a 90 degree clockwise rotation?

Mathematics
1 answer:
vodomira [7]3 years ago
6 0
The answer will be A....
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It would be nice if somebody could help me! (I'm trying to give out points!)
maw [93]

Answer:

chupapi muyanyo

Step-by-step explanation:

3 0
3 years ago
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This is pre calculus please help !Describe three ways to determine the measure of segment YZ.
Dmitry [639]
(1) Using trigonometric ratios:
sin(30) = \frac{YZ}{50}
YZ = 25

(2) Using Pythagoras' Theorem:
cos(30) = \frac{XY}{50}
50cos(30) = XY
50^{2} - 50^{2}cos^{2}(30) = YZ^{2}
2500 - 2500cos^{2}(30) = YZ^{2}
YZ = 25

(3) Using sine rule:
\frac{50}{sin(90)} = \frac{YZ}{sin(30)}
50 = \frac{YZ}{sin(30)}
50sin(30) = YZ
YZ = 25
7 0
3 years ago
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Shirley is decorating the gym for a party. She has 5 rolls of blue streamer and 9 rolls of green streamer. If each roll of blue
sp2606 [1]

Answer:

987 ft.

Step-by-step explanation:

We can solve this with an equation.

Since she has 5 rolls of 99 feet long blue streamer, then she has 5*99=495 feet of blue streamer

Since she has 9 rolls of 88 feet long blue green, then she has 9*88=792 feet of blue green

To find the total, we can add them up and get 495+792=987

8 0
2 years ago
Find the odd man out. 15,25,30,51,85,90,115 A.15 B.25 C.51 D.90
kirill [66]
The answer is C. 51 because we can see that all of the numbers are divisble by 5 except for 51
an easy way to tell is if the number ends in 0 or 5, it is divisible by 5
51 is the only one that doesn't end in 0 or 5 so it isn't divisible by 5 (it's divisible by 3 and 17)

the answer is C. 51
4 0
3 years ago
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Which expression is equivalent to StartFraction (3 m Superscript negative 1 Baseline n squared) Superscript negative 4 Baseline
koban [17]

Answer:

3m^{10}n^{-11}

Step-by-step explanation:

Given the expression \frac{(3m^{-1}n^{2})^{-4}   }{(2m^{-2}n)^{3}  }, we will use laws of indices to get the equivalent expression as shown below;

According to one of the law of indices,

\frac{a^{m} }{a^{n} } = a^{m-n}  \ and\ (a^{m})^{n} = a^{mn}

\frac{(3m^{-1}n^{2})^{-4}   }{(2m^{-2}n)^{3}  }\\= \frac{3m^{4}n^{-8}   }{2m^{-6}n^{3}  }\\= 3m^{(4-(-6))} * n^{-8-3}\\ = 3m^{10}n^{-11}

This gives the required expression

8 0
3 years ago
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