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beks73 [17]
3 years ago
13

Ralph and Waldo start in towns that are 70 miles apart and travel in opposite directions for 4 hours.

Mathematics
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

Step-by-step explanation:

Let Waldo's speed = W

Let Ralph's speed = W + 15

A

Waldo's distance = speed * Time

Time = 4 hours.

Speed = w

distance = 4 * w

B

Ralph's speed is W + 15. It's not clear if you need a number. We'll get around to that later.

C

Ralph traveled  4*(W + 15)

D

4w + 70 + 4(W + 15) = d

You really can't get a definite answer to these questions. Even if you knew whether they were heading away from each other or towards each other it wouldn't help.

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Nick and Adam workout together. Nick weighs 160 pounds and is gaining about 3 pounds per week. Adam weighs 195 pounds and is los
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There are 10 employees in a particular division of a company. Their salaries have a mean of $70,000, a median of $55,000, and a
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Answer:

A) bar{x}_{new}=160,000

B) Median remains the same.

C) sigma_{new}=300998.34

Step-by-step explanation:

Consider the complete question attached below.

No. of employees = n = 10

Given mean = $70,000

Median = $55,000

Standard deviation = $60,000

Largest number on the list = $100,000

Accidentally changed to = $1,000,000

Modified mean, media, SD =?

A) Modified Mean:

\bar{x}=\frac{\sum x}{n} = 70,000\\\\\sum x=(\bar{x})(n) = (70,000)(10)\\\\\sum x=700,000\\\\\sum x_{new} =700,000 -100,000+1,000,000\\\\\sum x_{new}=1,600,000\\\\\bar{x}_{new}=\frac{1,600,000}{10}\\\\\bar{x}_{new}=160,000

B) Modified Median:

Median remains same and is not affected by changing highest value.

C) Modified SD:

Standard deviation is given by formula:

\sigma=\sqrt{\frac{\sum x^{2}-n\bar{x}}{N-1}}---(1)\\\\\sigma_{new}=\sqrt{\frac{\sum x_{new}^{2}-n\bar{x}_{new}}{N-1}}---(2)\\\\From\,\, (1)\\\\\sum x^{2}=(N-1)\sigma^{2}+n\bar{x}

\sum x^{2}=(10-1)(60,000)^{2}+(10)(70,000)^{2}\\\\\sum x^{2}=8.14\times 10^{10}\\\\\sum x_{new}^{2}= 8.14\times 10^{10}-(10,0000)^{2}+(1,000,000)^{2}\\\\\sum x_{new}^{2}=1.0714\times 10^{12}\\\\Using\,\, (2)\\\sigma_{new}=\sqrt{\frac{1}{9}(1.0714\times 10^{12}-(10)(1.6\times 10^{5})}\\\\\sigma_{new}=\sqrt{9.06\times 10^{11}}\\\\\sigma_{new}=300998.34

7 0
3 years ago
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