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3 years ago

What is the domain of the function f(x)=x^2+3x+5?

Mathematics

2 answers:

Ugo [173]3 years ago

8 0

Answer:

all real numbers

Step-by-step explanation:

Kitty [74]3 years ago

4 0

Answer:

The domain of this function is all real numbers

Step-by-step explanation:

Unless there is a domain restriction for the function, the domain of a function is all real numbers. This means that all we need to do is determine whether there is a domain restriction.

The things that cause a domain restriction are: an x in the denominator of a fraction like $f(x)=\frac{1}{x}$ or a radical like $f(x)=\sqrt{1-x}$

As there are no variables in the denominator or a radical, we can conclude that the domain of this function is all real numbers.

You might be interested in

Calculate volume of hemisphere with radius 3.2 cm

Olin [163]

Answer:

V ≈ 68.63 cm³

Step-by-step explanation:

the volume (V) of a sphere is calculated as

V = $\frac{4}{3}$ πr³

the volume of a hemisphere is half the volume of a sphere, so

V = $\frac{1}{2}$ × $\frac{4}{3}$ πr³ = $\frac{2}{3}$ πr³ , then

V = $\frac{2}{3}$ π × 3.2³

= $\frac{2}{3}$ π × 32.768

≈ 68.63 cm³ ( to 2 dec. places )

5 0

2 years ago

Can someone help me with this problem please? I'll mark you as brainliest!

leonid [27]

Answer:

put a closed for on -1 and go to the left with an arrow

3 0

3 years ago

Read 2 more answers

The formula m = 12,000 + 12,000rt 12t gives Keri's monthly loan payment, where r is the annual interest rate and t is the length

alexandr1967 [171]

Answer:

$240

Step-by-step explanation:

Fill in the given numbers and do the arithmetic.

$m=\dfrac{12,000+12,000rt}{12t}=\dfrac{12,000+12,000\cdot 0.04\cdot 5}{12\cdot 5}\\\\m=\dfrac{14,400}{60}=240$

Keri's monthly loan payment is $240 per month.

3 0

3 years ago

Read 2 more answers

In isosceles $\triangle abc$ (with $ab = ac$), point $d$ lies on $ab$ such that $cd = cb$. if $\angle adc = 115^\circ$, what is

Nuetrik [128]

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Answer: 15°.

3 0

3 years ago

Read 2 more answers

I need to know how to do the answer and why that’s the anwer

Pavel [41]

Ok so the answer is
$4 {x}^{2}$

so we multiply numbers that have the same variable

$2 {x}^{3} \: \: \times {2x}^{ - 1} \\ \\$
multiply 2 x 2

$2 \times 2 = 4$
then multiply the exponents

$x ^{3} \times x ^{ - 1}$
multipling like this will look like addition.
${x}^{3} \times {x}^{ - 1} = {x}^{2}$
so in other words you could do it like this too
${x}^{3} + {x}^{ - 1} = {x}^{2}$
now add the exponent with 4
$4 + {x}^{2} = 4x ^{2}$

now for the last part
${y}^{3} + {y}^{ - 3} = 0$
because -3 and 3 added together make 0
$0 + 4 {x}^{2} = 4 {x}^{2}$
I hope this help(it looks complicated but it's very easy and I hope I helped you out)

6 0

3 years ago