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Nesterboy [21]
3 years ago
11

A box contains 6 plain pencils and 2 pens. A second box contains 5 colored pencils and 7 crayons. One item from each box is chos

en at random. What us the probability that a plain pencil from the first and a color from the second are selected?
Mathematics
1 answer:
Lena [83]3 years ago
6 0
11 this is your answeri hope
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Iliana’s math grade increased from 65 to 86. Fiona’s math grade increased from 70 to 80. What is the difference, rounded to the
boyakko [2]
I-F=100(86-65)/65 - 100(80-70)/70 = 18%

Iliana's increase was 18% more than Fiona's increase.
5 0
3 years ago
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24. Given the number -
maxonik [38]

answer v yes yes yes yes yes

3 0
3 years ago
A customer wants you to enlarge a photo to 22 its current height. The photo's current height is 31 inches. What should its enlar
stiks02 [169]

Answer:

The enlarged height of the photo must be 682 inches

Step-by-step explanation:

A customer wants to enlarge the image by 22 times

Hence, the scale factor = +22

Now, the current height of the photo = 31 inches

Therefore, to find the enlarged height : we need to multiply the scale factor of the required image by the current height of the photo.

Hence, Enlarged Height = 22 × 31

                                         = 682 inches

So, The enlarged height of the photo must be 682 inches

8 0
3 years ago
Please let me know if you guys can get this.!
geniusboy [140]

Answer:

c

Step-by-step explanation:

4 0
2 years ago
PLEASE HELP! 100 POINTS!!+ BRAINLIEST!!
Karolina [17]

<em>Height of the pole (DC) is 57.2709m</em>

Step-by-step explanation:

Here, Wire DA and Wire DB supports a pole.

Given that Angle, A=54 , B= 72.

Also, AB = 23m

Now, Taking triangle BCD and Using basic trigonometry

Height of pole H = DC

TanB = \frac{DC}{BC}

BC= \frac{DC}{TanB}

Now, Taking triangle ACD and Using basic trigonometry

TanA = \frac{DC}{AC}

AC= \frac{DC}{TanA}

From figure, we know that

AC = AB + BC

AC - BC = AB = 23

Replacing values of AC and BC

\frac{DC}{TanA} - \frac{DC}{TanB}=23\\DC(\frac{1}{TanA}-\frac{1}{TanB})=23

Now, TanB= Tan72 =3.0776 and TanA = Tan54=1.3763

DC (\frac{1}{1.3763} - \frac{1}{3.0776})_= 23

DC ( 0.7265-0.3249)= 23

DC ( 0.4016 )= 23

DC = 57.2709

Thus, Height of thepole is 57.2709m

5 0
3 years ago
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