Sin 45° = opposite side / hypotenuse
1/2 = 8/h
h = 16
2)6/12 = 1/2
1/2 = sin 45°
6√3/12 = √3/2
√3/2 = cos 30°
Sum of angles of triangle = 180°
The 3rd angle = 180 - (45 + 30) = 180 - 75 = 105°
Angles = 30° , 45° , 105°
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
f(x) = √3x
g(x) = √48x
(f . g)(x) = ?
Step 02:
(f . g)(x) :
![\text{ (f.g)(x) = }\sqrt[]{3(\sqrt[]{48x)}}](https://tex.z-dn.net/?f=%5Ctext%7B%20%20%20%20%20%20%20%20%20%20%28f.g%29%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B3%28%5Csqrt%5B%5D%7B48x%29%7D%7D)
![(f.g)(x)\text{ = }\sqrt[]{3(48x)^{\frac{1}{2}}}\text{ }](https://tex.z-dn.net/?f=%28f.g%29%28x%29%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B3%2848x%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%5Ctext%7B%20%7D)
(f.g)(x) = 12 √ x
The answer is:
(f.g)(x) = 12 √ x
Answer:
2/3
Step-by-step explanation:
fraction of book already read = 1/3
fraction which represents whole book = 1 = 3/3
fraction of remaining book = fraction of whole book - fraction of book already read
= 1 - 1/3
= 3/3 - 1/3
= (3-1) /3
= 2/3
Answer:
a) The interval for those who want to go out earlier is between 43.008 and 46.592
b) The interval for those who want to go out later is between 47.9232 and 51.9168
Step-by-step explanation:
Given that:
Sample size (n) =128,
Margin of error (e) = ±4% =
a) The probability of those who wanted to get out earlier (p) = 35% = 0.35
The mean of the distribution (μ) = np = 128 * 0.35 = 44.8
The margin of error = ± 4% of 448 = 0.04 × 44.8 = ± 1.792
The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)
b) The probability of those who wanted to start school get out later (p) = 39% = 0.39
The mean of the distribution (μ) = np = 128 * 0.39 = 49.92
The margin of error = ± 4% of 448 = 0.04 × 49.92 = ± 1.9968
The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)
The way for those who want to go out earlier to win if the vote is counted is if those who do not have any opinion vote that they want to go earlier
Answer:
4 times 312 = 1,248 = 312 times 4 = 1,248
Hope this helps, sorry if it didn't.