Given:
Atul has
lb of candy.
Jose has
lb of candy.
Maria has
lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has
lb less than Jose, therefore
Maria has =
lb
Maria has =
lb
Maria has =
lb
Difference between the candies Atul and Maria have.
Difference =
lb
Difference =
lb
Difference =
lb
Therefore, Atul have
lb of candy more than Maria.
Answer:
<u>1. x^2 + (absolute value) X</u>
<u>2. x^2 - (absolute value) X</u>
<u>3. x^2 * (absolute value) X</u>
Step-by-step explanation:
Add equations for 1.
Subtract equations for 2.
Multiply equations for 3.
I got 200 from a octagon with the diameter of 10
Answer:
if it's me I would pick etherbc are d I holp it helps