Question

50 points for this one

Answer 1

Answer:

-1, 0

Step-by-step explanation:

Hello!

We can test each solution for by substituting the value for x, and see if the inequality is true.

x = -1:

• $\frac{3(-1)^2}{(-1)^2+3} < 1$
• $\frac34 < 1$

This inequality is true.

x = -2:

• $\frac{3(-2)^2}{(-2)^2+3} < 1$
• $\frac{12}{7} < 1$

This inequality is not true because 12/7 is greater than 1.

x = 0:

• $\frac{3(0)^2}{(0)^2+3} < 1$
• $0 < 1$

This is inequality is true.

x = 3:

• $\frac{3(3)^2}{(3)^2+3} < 1$
• $\frac{27}{12} < 1$

This inequality is not true because 27/12 is greater than 1.

The solutions that work are -1 and 0.

Answer 2

Answer: A

Step-by-step explanation: