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3 years ago

Figure A has a radius of 2 inches. It is dilated by a scale factor of 4 to form figure B. What is the radius of figure B?

1 answer:

7 0

Given that figure A with radius of 2 inches is dilated to form figure B, the radius of B will be given by:
Radius B=(radius A)×(scale factor)
but
scale factor=4
thus
Radius of B will be:
2×4
=8 inches

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Find the perimeter of quadrilateral ABCD with vertices A(-2,-2), B(-1,3),

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Answer:

Step-by-step explanation:

Step one

given the coordinates

ABCD with vertices A(-2,-2), B(-1,3), C(5, 3), and D(4, -2)

AB=(-2,-2),(-1,3)

BC=(-1,3), (5, 3)

CD=(5, 3),(4, -2)

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The distance between points AB=

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$AB= \sqrt (-1+2)^2+(3+2)^2\\\\AB= \sqrt 1^2+(5)^2\\\\AB= \sqrt26\\\\AB=5.1$

The distance between points BC=

$BC= \sqrt (5+1)^2+(3-3)^2\\\\BC= \sqrt 6^2+(0)^2\\\\BC= \sqrt36\\\\BC=6$

The distance between points CD

$CD= \sqrt (4-5)^2+(-2-3)^2\\\\CD= \sqrt -1^2+(-5)^2\\\\CD= \sqrt26\\\\CD=5.1$

The distance between points DA

$DA= \sqrt (4+2)^2+(-2+2)^2\\\\DA= \sqrt 6^2+(0)^2\\\\DA= \sqrt36\\\\DA=6$

Hence the perimeter = 5.1+6+5.1+6

= 22.2

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