Hello there!
The correct answer is D. 8.
Hope This Helps You!
Good Luck :)
Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.
In a <em>normal distribution</em> with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 90 grams, hence
.
- The standard deviation is of 1 gram, hence
.
We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:



The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.
- Looking at the z-table, Z = -3 has a p-value of 0.0013.
2 x 0.0013 = 0.0026
0.0026 x 100% = 0.26%
0.26% of the items will either weigh less than 87 grams or more than 93 grams.
For more on the normal distribution, you can check brainly.com/question/24663213
Answer: I believe it’s 1,-1. not 100% but pretty positive it is! hope this helps!
either
-(3x+3)-2x (less than) -4(x-2)-2
-3x+3-2x (less than) -4x +8-2
-5x+3 (less than)-4x+6
Or if you need it simplified
-5x +3 (less than) -4x+6
+4x 4x
-x+3 (less than) 6
-3 -3
-x(less than) 3
(-x/-1) Less than (3/-1)
x (less than) -3
(didnt have the less than greater than sign so typed it)