Answer:
100% or 1
Explanation:
This question involves a gene coding for fur color in bears. According to the question, black fur allele (B) is dominant over the brown fur allele (b). This means that a bear heterozygous for fur color (Bb) will be phenotypically black.
In this question, a black father bear (genotype BB) and a brown mother bear (genotype bb) were crossed, the baby bears will all have a genotype Bb (see punnet square in the attached image). Since all the offsprings of this cross have genotype Bb, this means that 100% will have black fur.
The probability that the resulting child will not inherit the disease is 25%.
<h3>Probability in genetics</h3>
Assuming that the disease is represented by the allele A (a). Huntington's disease is autosomal dominant.
Thus, the genotypes of the two parents will be Aa each.
Aa x Aa
AA Aa Aa aa
Probability of the child having Huntington's = 3/4 or 75%
Probability of the child not having Huntington's = 1/4 or 25%
More on Huntington's can be found here: brainly.com/question/12572808
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Fitness =being healthy adaptations=being able to adapt to your surrondings
Answer:
False.
Explanation:
Pseudoscience are not exact and precise. In fact, they are mistaken practices/methods that are not part of the scientific method or based on the scientific method.