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Anna11 [10]
3 years ago
6

Last month, 349 books were checked out from the school library. This month, 273 books were checked out. Find the Percent of Chan

ge from Last Month to This Month.
Mathematics
1 answer:
Alexeev081 [22]3 years ago
8 0
Last month to this month
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Gia got some books from Library yesterday she got five books today Gia returned three books Gia has six books how many books did
makvit [3.9K]

Answer: 4


Explanation:


You can write an algebraic expression to represent the sequence with the books in this way:

  • yesterday she got five books: 5
  • today returned three books: - 3
  • how many books did Gia have to begin: n
  • At the end she has six books, which means that you can set an equality:

       n + 5 - 3 = 6

Now you follow these steps to clear the unknown:

  • do the operations in the left side: n + 2 = 6
  • use subtraction property of equality: n = 6 - 2
  • do the operations: n = 4

And that is the number of books whith which Gina started: 4

6 0
2 years ago
-1(-2x + 4) = 6<br><br> Hellooooooooooo
butalik [34]

Answer:

x=5

Step-by-step explanation:

First we distribute

2x-4=6

isolate x

2x=10

divide both sides by 2

x=5

(plz give brianliest ty)

6 0
3 years ago
Read 2 more answers
The area of the rectangle shown is 200 square units. Find the value of x?
Stels [109]

Answer:

x=40

Step-by-step explanation:

8(1/2x + 5) = 200

4x + 40 = 200

4x = 160

x = 40

6 0
3 years ago
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Which ordered pair is a solution to the system of linear equations Negative 4 x + y = 8 and x minus 5 y = 17?
Zinaida [17]

Answer:

(-3, -4).

Step-by-step explanation:

-4x + y = 8

x - 5y = 17           Multiply this by 4:

4x - 20y = 68     Add this to the first equation:

-19y = 76

y = 76/-19

y = -4.

Plug this into the second equation:

x - 5(-4) = 17

x = 17 - 20

x = -3.

CHECK this result in equation 1:

-4(-3) + -4 =  8

12 - 4 = 8

8 = 8  <------ OK.

8 0
2 years ago
180 product of a prime factor using indices
zvonat [6]
Start with 180. 
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>

<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>

<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>

<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>

<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>

<span>Once you end up with a quotient of "1" you're done. </span>

<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
5 0
2 years ago
Read 2 more answers
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