Answer:
Step-by-step explanation:
3 consecutive integers....
1st integer = x
2nd integer = x + 1
3rd integer = x + 2
the product of 1st and 3rd is 5 greater then 5 times the 2nd...
x(x+2) = 5(x + 1) + 5
x^2 + 2x = 5x + 5 + 5
x^2 + 2x = 5x + 10
x^2 + 2x - 5x - 10 = 0
x^2 - 3x - 10 = 0
(x - 5)(x + 2) = 0
x - 5 = 0 x + 2 = 0
x = 5 x = -2
so it will be : 5,6,and 7 or -2,-1, and 0
Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
The sampling error if the grade point averages for 10 randomly selected students from a class of 125 students has a mean of x =2. is A. -0.7.
Given:
Random number=10
mean of x=2
population=125
mean of p=2.7
Using this formula
Sampling error=x− μ
Where:
x= sample mean=2
μ=population mean=2.7
Let plug in the formula
Sampling error=2-2.7
Sampling error=-0.7
Inconclusion the sampling error is A.-0.7.
Learn more here:
brainly.com/question/13929265
