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Bingel [31]
3 years ago
13

8675 divested by .50 solved

Mathematics
2 answers:
vladimir2022 [97]3 years ago
7 0
It is 173.5 because if youl mulitipy 2 times 173.5 it equal to 8,675
Gnoma [55]3 years ago
6 0
8675 ÷ .5 = 17350
(you could also multiply by 2)
to check your answer:
17350 x .5 = 8675
(you could also divide by 2 #samething)
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Match each equation with a solution from the list of values.
vova2212 [387]

Answer:

1. a=2.3

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3. c=2.3

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Step-by-step explanation:

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2 years ago
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You are working on an experiment where you want to test the effects of caffeinated beverages on the behavior of cats. You will t
vichka [17]
For the experiment, you need 2L of cola. Your first option would be to purchase 1 2L bottle of cola for $2.25. 

To calculate the second option, let's convert milliliters to liters first. There are 1,000 milliliters in 1 liter. With this, we know that there are 2,000 milliliters in 2 liters. Option 2 comes in 500-milliliter cans, which means that you would need 4 of them (2,000/500 = 4). 4 cans multiplied by $0.50 would cost you $2.00. 

Let's check the cost of your answer options.
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B. 1 bottle - From the question, we know this would cost $2.25.
C. 2 bottles - This would be more soda than you need and would cost $4.50 ($2.25x2)
D. 1 can - This would be .5L and not enough soda for the experiment.
E. 5 cans - This would cost $2.50, but would be an extra 500mL of soda.
F. 2 cans - This would only be 1L of soda and not enough for the experiment.
G. 3 cans - This would be 1.5L of soda and not enough for the experiment either.

For the best price option, you would choose A (four cans of soda). This would give you the amount of soda that you need at the lowest price.
6 0
3 years ago
The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(
SVEN [57.7K]

d = 3 , a₁₂ = 40 and Sx_{100} = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• an = a₁ + (n-1)d</h3><h3>• S_n = \frac{n}{2}[2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = \frac{50}{2}[(2×7) +(99×3)</h3><h3>       = 25(14 + 297) = 25(311)= 7775</h3>
7 0
3 years ago
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