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3 years ago

In the figure, if m∠ABD = 120º, then m∠ADC =? º.

Mathematics

2 answers:

Anna11 [10]3 years ago

4 0

The figure that this question is referring to is attached. We must use the Law of Sines to solve this question, which is as follows:

a/sinA = b/sinB = c/sinC

This applies to any triangle. We are told that ∠ABD = 120º. We are asked to solve for ∠ADC. We know that ∠ADC + ∠ADB = 180º. If we assign ∠ADC = x, then ∠ADB = 180<span>º - x. We can now apply the law of sines to this data.

35/sin120 = 30/sin(180-x)
sin(180-x) = (30/35)(sin120)
sin(180-x) = 0.742
sin-1(sin(180-x)) = sin-1(0.742)
180 - x = 48</span><span>º
x = 132</span><span>º
</span>
We have already assigned x = ∠ADC; therefore, ∠ADC = 132<span>º.</span>

Andru [333]3 years ago

4 0

The correct answer is

132

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3 years ago

P( rolling a number greater than 2 and the coin landing on heads or tails)

irina [24]

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<h3>How to determine the probability?</h3>

The given parameters are:

Objects = Dice and Coin

The sample space of the objects are:

Dice = {1, 2, 3, 4, 5, 6}

Coin = {Head, Tail}

From the above sample spaces, we have:

P(Rolling a number greater than 2) = 4/6

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The required probability is then calculated as:

P(rolling a number greater than 2 and the coin landing on heads or tails) = P(Rolling a number greater than 2) * P(Coin landing on heads or tails)

Substitute the known values in the above equation

P(rolling a number greater than 2 and the coin landing on heads or tails) = 4/6 * 1

Evaluate the product

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