Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)
moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g
Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05
N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
56 miles, The car traveled m miles during the first hour and m squared miles during the second hour. The ratio m/m squared = 1/7 and cross multiplying yields m squared = 7m, so m=7. This means that the total distance traveled was 7+7squared = 56 miles
8.3 is the decimal for the first model and for the second model it is 4.8. Now you just need to add them and you should get 13.1 as your answer. If helped mark me the brainiest!!
Answer:
The equation of the function in slope-intercept form is y = 3 x + 5 .
Step-by-step explanation:
Given as :
A line passes through the point ( - 1 , 2 )
i.e ( x , y ) = ( - 1 , 2 )
The slope of the line is 3
The equation of line in slope intercept form
y - 
= m ( x - 
)
Where m is the slope of the line
So, y - 2 = 3 ( x - ( - 1 ) )
Or, y - 2 = 3 ( x + 1 )
Or, y - 2 = 3 x + 3
Or, y = 3 x + 3 + 2
∴ y = 3 x + 5
Hence The equation of the function in slope-intercept form is y = 3 x + 5 . Answer
