Edge computing be used to increase sustainability With Edge Computing the number of records traversing the network can be reduced greatly, freeing up bandwidth.
<h3>How is part computing sustainable?</h3>
Data centers devour an expected 2 hundred terawatt-hours (TWh) of power every year–extra than the power intake of a few countries. They additionally produce an expected 2% of all worldwide CO2 emissions. Edge Computing reduces network site visitors and records centre usage.
Data centres devour an expected 200 terawatt-hours (TWh) of power every year–extra than the power intake of a few countries. They additionally produce an expected 2% of all worldwide CO2 emissions.
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Answer:
"A graphics package is an application that can be used to create and manipulate images on a computer. There are two main types of graphics package: painting packages."
Explanation:
i looked it up like a normal person
jeez does nobody use google on here lol
Th answer to your question is Endpoint
The factor that is helpful when adding new inventory and not among the Accounting Functions is the audit function.
<h3>Why is the audit function important?</h3>
The role of internal audit is known to be one that tends to give some measures of independent assurance that is need by a firm or an organization in terms of risk management, governance, as well as internal control processes to be able to operate effectively.
Note that an internal audit is said to be carried out objectively and set up to improve and make good an organization's business practices.
Hence, The factor that is helpful when adding new inventory and not among the Accounting Functions is the audit function.
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Answer:
0.8488
Explanation:
Let E =error found by test 1
Let F=error found by test 2
Let G=error found by test 3
Let H=error found by test 4
Let I= error found by test 5
Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5
therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5
Tests are independent P(not E & not F ¬ G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512
P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488
