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masha68 [24]
3 years ago
12

Which expression gives the length of the transverse axis of the hyperbola

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer:

Option (B)

Step-by-step explanation:

From the picture attached,

F1 and F2 are the focii of the hyperbola.

Point P(x, y) is x units distant from F1 and y units distant from the other focus F2.

By the definition of a hyperbola,

"Difference between the distances of a point from the focii is always constant and equals to the measure of transverse axis."

Difference in the distances of point P from focii F1 and F2 = (x - y) units

This distance is equal to the length of the transverse axis = (x - y) units

Therefore, Option (B) will be the answer.

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What are the vertical asymptote(s) and hole(s) for the graph of y =
Murljashka [212]

Answer:

asymptotes: x= -4,-2 and no holes

Step-by-step explanation:

First we need to factor the denominator of the function

y = (x-1) / (x2 + 6x + 8)

x2 + 6x + 8 = 0

delta = b2 - 4ac = 36 - 32 = 4

x1 = (-6 + 2) / 2 = -2

x2 = (-6 - 2) / 2 = -4

So we have that x2 + 6x + 8 = (x+4)(x+2)

So our function is:

y =  (x-1) / (x+4)(x+2)

As there is no common expressions in the numerator and denominator, there are no holes.

The asymptotes are when the denominator is zero, so:

(x+4)(x+2) = 0

x = -4 or x = -2

6 0
3 years ago
How do i work out the probability of rolling two sixes
Olegator [25]

Answer: p = 1/25

Step-by-step explanation:

Ok, you know that the probability of rolling a six is p = 1/5

now, if you want to have two sixes, then you have two events with a probability of 1/5.

And as you know the joint probability for two events is equal to the product of the probabilities, then the probability of rolling two sixes is:

p = (1/5)*(1/5) = 1/25.

5 0
3 years ago
Can someone help me with this question?
Amanda [17]

Answer:

angle ABE and DBC

Step-by-step explanation:

They are both greater than 90 degrees

4 0
3 years ago
Read 2 more answers
Your friend claims that it is possible to draw a right triangle where the cosine of either angle (theta) is exactly the same val
avanturin [10]

Answer:

B. No

Cos \ \theta\neq Cos (90-\theta)\textdegree

Step-by-step explanation:

-A right angle triangle has two complimentary acute angles and one right angle.

-\theta is usually one of the acute angles and is equivalent to 90º minus it's complimentary acute angle.

-Complimentary angles add up to 90º.

#For complimentary angles:

Sin \ \theta=Cos \ (90-\theta)\textdegree\\\\Cos \ \theta=Sin(90-\theta)\textdegree\\\\\therefore Cos \ \theta\neq Cos (90-\theta)\textdegree

The two acute angles cannot have the same Cosine value.

Hence, she's not correct.

5 0
3 years ago
Solve kx + 7 = 4 for x.
svlad2 [7]

Answer: x=-3/k

Step-by-step explanation:

kx + 7 = 4

kx=4−7

kx=−3

x=-3/k

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

9 0
3 years ago
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