The solubility of sodium nitrate in water is .8 g/ml at 0 degrees celsius. the solubility increases to 1.9 g/ml at 180 degrees c
1 answer:
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2M
Explanation:
Given that:
V1 = 50mL
M1 = 40M
V2 = 1000mL
unknown:
M2 = ?
Solution:
Concentration is the number of moles solute in a solution.
Since the number of moles in the solute remains the same;
Concentration =
number of moles = concentration x volume
Number of moles before and after the dilution remains the same;
M1 x V1 = M2 x V2
M1 is initial concentration
V1 is initial volume
M2 is final concentration
V2 is final volume
40 x 50 = M2 x 1000
M2 = 2M
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Explanation:
1 mol of Ba(OH)2 = 2 moles of HCl
