What is the consecration of a solution that is made by diluting 50.0 mL of a 40.0 M NaCl solution to a final volume of 1000.0 mL
1 answer:
2M
Explanation:
Given that:
V1 = 50mL
M1 = 40M
V2 = 1000mL
unknown:
M2 = ?
Solution:
Concentration is the number of moles solute in a solution.
Since the number of moles in the solute remains the same;
Concentration =
number of moles = concentration x volume
Number of moles before and after the dilution remains the same;
M1 x V1 = M2 x V2
M1 is initial concentration
V1 is initial volume
M2 is final concentration
V2 is final volume
40 x 50 = M2 x 1000
M2 = 2M
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Answer:
The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Explanation:
The formation reaction of CH_3OH will be,
The intermediate balanced chemical reaction will be,
..[1]
..[2]
..[3]
Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, Using Hess's law:
We get :
..[1]
..[2]
[3]
The expression for enthalpy of formation of will be,
The standard enthalpy of formation of methanol is, -238.7 kJ/mole