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Mathematics

2 answers:

Harman [31]3 years ago

8 0

here we have 3X to 5 seventh power in radical form

$3x^{5/7}$

we need write this in radical form we knwo that $x^{1/2} =\sqrt{x}$

so $3x^{5/7} =\sqrt[7]{3x^{5}}$

this will be the radical form .

grigory [225]3 years ago

6 0

Answer:

3 $\sqrt[7]{x}^5$

Step-by-step explanation:

Its not like a method, that is just where you are suppose to put the numbers together. If you memorize the denominator goes on the outside and the numerator inside, it would help a lot.

<em>Btw I took the test and got it correct so please please please gimme brainliest answer.</em>

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Please find the value of this one expression

Masja [62]

Answer:

Solving the expression $\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)$ we get 6

The answer is 6.

Step-by-step explanation:

We need to find value of expression: $\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)$

We know that $\sqrt{81}=9$

Our expression will become

$\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{9 } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-2 -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-4)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4$