Answer:
13/20
Step-by-step explanation:
65%=65/100
65/100=13/20
Answer:
the answer is 15
Step-by-step explanation:
density= total population/surface area
density= 375/5^2
density=375/25=15
Divide into shapes that you can find the area of.....
you also have to cross out the 5 and the 4s because you will not need them
2×2= 4 sq. cm
2×2= 4 sq. cm
9×2 = 18 sq. cm
18 + 4 + 4 = 26 sq. cm
so the area is 26 sq. cm
Answer:
yea
Step-by-step explanation:
Let

, so that

,

, and

. Then

Now let

, so that

. Then

Transform back to

to get

and again to get back a result in terms of

.