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To solve this, it might be easier to draw it out (see the picture below). I split it into two triangles and used trig functions to find the altitude. I used the big triangle to find theta, and the used theta to find the side of the altitude. *remember that sine= opposite/hypotenuse*
Answer:
perimeter = 28.13 cm
Step-by-step explanation:
Calculate the length of a line drawn from A to C.
sin 85 = b/8, b = 7.97
cos 85 = c/8, c = 0.697
AC² =7.97² + (6 + 0.697)² = 63.52 + 44.85 = 108.37
AC = 10.41
Now you have a right triangle ADC with a known hypotenuse and one leg.
Using the Pythagorean theorem:
DC² = 10.41² - 5²
DC² = 108.37 - 25 = 83.37
DC = 9.13 cm
perimeter = 5 + 6 + 8 + 9.13 = 28.13 cm
Answer:
Perpendicular lines have opposite-reciprocal slopes, so the slope of the line we want to find is 1/2. Plugging in the point given into the equation y = 1/2x + b and solving for b, we get b = 6. the equation of the line is y = ½x + 6.
Step-by-step explanation:
found off google
Answer:
your answer is correct.
Step-by-step explanation:
For the purpose here, we'll call the missing point on the arc through Z point X.
Essentially, you want to make ΔXYZ ≅ ΔLMN by SSS. The construction so far ensures LM ≅ MN ≅ XY ≅ YZ. By copying the length LN to XZ, you ensure the congruence of the remaining sides of the triangles.
Then ∠XYZ ≅ ∠LMN because corresponding parts of congruent triangles are congruent.
In short, XZ needs to be the same distance as LN.
