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Brrunno [24]
3 years ago
15

What is the remainder when 19x^2 + 15x + 12 is divided by x - 2?

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

R = 118

Step-by-step explanation:

Given

Represent the polynomial with P and the divisor with D

P = 19x^2 + 15x + 12

D = x -2

Required

Determine the remainder

We start by equating the divisor to 0

i.e.

D = 0

x - 2 = 0

x = 2

Substitute 2 for x in the polynomial.

This gives remainder (R)

R = 19*2^2 + 15*2 + 12

R = 19*4 + 15*2 + 12

R = 76 + 30 + 12

R = 118

<em>Hence, the remainder is 118</em>

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A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
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Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
3 years ago
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