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3 years ago

15

What is the remainder when 19x^2 + 15x + 12 is divided by x - 2?

1 answer:

Aleksandr-060686 [28]3 years ago

8 0

Answer:

R = 118

Step-by-step explanation:

Given

Represent the polynomial with P and the divisor with D

$P = 19x^2 + 15x + 12$

$D = x -2$

Required

Determine the remainder

We start by equating the divisor to 0

i.e.

$D = 0$

$x - 2 = 0$

$x = 2$

Substitute 2 for x in the polynomial.

This gives remainder (R)

$R = 19*2^2 + 15*2 + 12$

$R = 19*4 + 15*2 + 12$

$R = 76 + 30 + 12$

$R = 118$

<em>Hence, the remainder is 118</em>

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