Answer:
![\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B2%7D)
Step-by-step explanation:
![\sqrt[4]{\sqrt[3]{2^2}} =((2^2)^\frac{1}{3})^\frac{1}{4}\\\\=(2^2)^\frac{1}{12}\\\\=2^\frac{2}{12}\\\\=2^\frac{1}{6}\\\\=\sqrt[6]{2}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Csqrt%5B3%5D%7B2%5E2%7D%7D%20%3D%28%282%5E2%29%5E%5Cfrac%7B1%7D%7B3%7D%29%5E%5Cfrac%7B1%7D%7B4%7D%5C%5C%5C%5C%3D%282%5E2%29%5E%5Cfrac%7B1%7D%7B12%7D%5C%5C%5C%5C%3D2%5E%5Cfrac%7B2%7D%7B12%7D%5C%5C%5C%5C%3D2%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%3D%5Csqrt%5B6%5D%7B2%7D)
Answer:
p<-3/8
Step-by-step explanation:
Answer:
My calculator said error and i tried looking it up it said error too. I'm sorry I tried, you'll have to do it by hand
Step-by-step explanation:
The answer is B. First solve the parentheses. Then make a quadratic equation and solve from there.
