Answer:
(C.) AC¯¯¯¯¯≅EG¯¯¯¯¯ is true
Step-by-step explanation:
The positions of the letters in naming the triangles in the statement of congruent tells you which sides are congruent.
△ABC≅△EFG
Sides AB and EF are congruent
△ABC≅△EFG
Sides BC and FG are congruent
△ABC≅△EFG
Sides AC and EG are congruent
Look at the choices:
(C.) AC¯¯¯¯¯≅EG¯¯¯¯¯ is true
Let me know is this one is right or incorrect
If it has no real solutions, that means the graph does not intersect the x axis
since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up
so 'a' must be positive
if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
Answer:
An equation of the circle with centre (-2,1) and radius 3 is 
Option D is correct.
Step-by-step explanation:
Looking at the figure we get centre of circle C (-2,1) and radius of circle r = 3
The equation of circle is of form: 
where (h,k) is centre and r is radius.
We have centre C (-2,1) so, we have h = -2 and k = 1
We have radius = 3 so, r = 3
Putting values in the equation and finding the required equation:
So, an equation of the circle with centre (-2,1) and radius 3 is
Option D is correct.
