Since 3 x 3 = 9, 9 is divisible by 3. So, 3 would be a factor of any number divisible by 9
For fog or f(g(x)), plug g(x) into f(x):
2(3x+2)²+x
Then simplify:
2( (3x+2)(3x+2) )+x
2( 9x²+12x+4 )+x
18x²+24x+8 +x
18x²+25x+8
Then you can simplify this further using factoring methods to:
(2x+1)(9x+8)
Hope this helps!! :)
X cannot equal +2, and can't be -1. If you factor it, then you notice you get 2(x+2)(x-2). If you use either one for the x, one will be zero and the won't, and vise-versa.
She spent $23.25, how I got my answer.
I divided $13.50÷2=$6.75 then I added $6.75+3=$9.75 then I added $9.75+$13.50=$23.25.
I hope this helps.