Answer:
Converting the equation
into completing the square method we get: ![\mathbf{(x-10)^2=87}](https://tex.z-dn.net/?f=%5Cmathbf%7B%28x-10%29%5E2%3D87%7D)
Step-by-step explanation:
we are given quadratic equation: ![x^2-20x+13=0](https://tex.z-dn.net/?f=x%5E2-20x%2B13%3D0)
And we need to convert it into completing the square method.
Completing the square method is of form: ![a^2-2ab+b^2=(a-b)^2](https://tex.z-dn.net/?f=a%5E2-2ab%2Bb%5E2%3D%28a-b%29%5E2)
Looking at the given equation ![x^2-20x+13=0](https://tex.z-dn.net/?f=x%5E2-20x%2B13%3D0)
We have a = x
then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20
So, 20x in form of 2ab can be written as: 2(x)(10)
So, we need to add and subtract (10)^2 on both sides
![x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87](https://tex.z-dn.net/?f=x%5E2-20x%2B13%3D0%5C%5Cx%5E2-2%28x%29%2810%29%2B%2810%29%5E2-%2810%29%5E2%2B13%3D0%5C%5C%28x%5E2-2%28x%29%2810%29%2B%2810%29%5E2%29%20%5C%3Acan%5C%3A%20be%5C%3A%20written%5C%3A%20as%5C%3A%20%28x-10%29%5E2%20%5C%5C%28x-10%29%5E2-100%2B13%3D0%5C%5C%28x-10%29%5E2-87%3D0%5C%5C%28x-10%29%5E2%3D87)
So, converting the equation
into completing the square method we get: ![\mathbf{(x-10)^2=87}](https://tex.z-dn.net/?f=%5Cmathbf%7B%28x-10%29%5E2%3D87%7D)
The answer would be 1.6. The way you do this problem is you square the hypotenuse(in this case 11.56), then subtract the squared version on the side you do have (in this case 9). Then when you subrtact the two, find the square root of the difference (which would be 1.6 in this case).
Answer:
D.
Step-by-step explanation:
First try to eliminate answers.
You have to work between 30 and 40 hours to get 1565.
It's not A or B.
Now, you can see that the choices are 31, and 35
1565 is only 15 more than 1550.
It's 31.
Answer:
hope it helps ya.
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