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Evgesh-ka [11]
3 years ago
14

Which could be the measures of angle POS and angle POQ

Mathematics
2 answers:
erastovalidia [21]3 years ago
6 0
This is the correct answer!!

Leno4ka [110]3 years ago
5 0

Answer:

Step-by-step explanation:

Measure of angle POS is 25 degrees, measure of angle POQ is 40 degrees

Measure of angle POS is 25 degrees, measure of angle POQ is 30 degrees

Measure of angle POS is 20 degrees, measure of angle POQ is 40 degrees

Measure of angle POS is 20 degrees, measure of angle POQ is 30 degrees

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A cylindrical pressure has a height of 9 feet and diameter of 6 feet. How much gas can the pressure vessel hold when full?
AleksAgata [21]

Answer:

81π ft³

Step-by-step explanation:

If the diameter is 6 ft, the radius is 3 ft.  

The volume is V = (area of base)(height).

Here,                V = (π[3 ft]²)(9 ft) = 81π ft³

3 0
3 years ago
Read 2 more answers
SOLVE THE QUESTION BELOW ASAP
qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have    

h(t)=-16t^{2}+98

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts,  and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

so

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

h(t)=-16(0)^{2}+98

h(0)=98

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

-16t^{2}+98=0

t^{2}=\frac{98}{16}

square root both sides

t=\pm\frac{\sqrt{98}}{4}

t=\pm7\frac{\sqrt{2}}{4}

therefore

The t-intercepts are

(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)

(-2.475,0), (2.475,0)

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

so

x=0 ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point (0,98)

The y-intercept is the point (0,98)

The t-intercepts are (-2.475,0), (2.475,0)

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

h(t)=-16(0)^{2}+98

h(0)=98\ ft

For t=1

h(t)=-16(1)^{2}+98

h(1)=82\ ft

Find the difference

98\ ft-82\ ft=16\ ft

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

h(t)=-16(1)^{2}+98

h(1)=82\ ft

For t=2

h(t)=-16(2)^{2}+98

h(2)=34\ ft

Find the difference

82\ ft-34\ ft=48\ ft

so

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from  t=0 to t=1

8 0
3 years ago
-2 3/4 ÷ -1/7= <br>help​
Hitman42 [59]

The answer is 19\frac{1}{4}

First you must set up the equation

-2\frac{3}{4}÷-\frac{1}{7}

First, you must make the mixed number a improper fraction

-\frac{11}{4}÷-\frac{1}{7}

Then you must divide

\frac{77}{4}

Finally, simplify

19\frac{1}{4}

3 0
3 years ago
Can some please help me?
PilotLPTM [1.2K]

Answer:

ofc 8374747374743i3i3i383

8 0
1 year ago
Read 2 more answers
Mold grows on bread and every day it doubles by the eighth day the entire bread is covered with mold when was half the bread cov
Brut [27]

Answer:

The mold will cover half the area as much are one day before it.

Step-by-step explanation:

Given:

Every day the mold on bread grows doubles

And by 8th day entire bread covered with it.

To Find:

When was half the bread covered by mold.

Solution:

It is said that area covered by mold doubles on each day

Total days taken to cover entire bread are 8

Let Area of bread be A

So Area covered (A) corresponds to 8 days with doubling.

So on previous day it should What ever area on 8th day/2

i.e A(8)/2

Similar on 6th day A(7)/2

So on 5ht day =A(6)/2 ,4th= A(5)/2,  on 3rd= A(4)/2, on 2nd=A(3)/2

On 1st =A(2)/2

So we required  Area= half of total.

<em>One day before the 8th day will be 7th day</em>

<em>on that day it will cover half are so that on next day will cover the double of the previous area consumed.</em>

4 0
3 years ago
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