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2 years ago

Which could be the measures of angle POS and angle POQ

Mathematics

2 answers:

erastovalidia [21]2 years ago

6 0

This is the correct answer!!

Leno4ka [110]2 years ago

5 0

Answer:

Step-by-step explanation:

Measure of angle POS is 25 degrees, measure of angle POQ is 40 degrees

Measure of angle POS is 25 degrees, measure of angle POQ is 30 degrees

Measure of angle POS is 20 degrees, measure of angle POQ is 40 degrees

Measure of angle POS is 20 degrees, measure of angle POQ is 30 degrees

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Simplified form of -3a5-(-2a5)

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32, 28, 21, 31, 18<br><br> Is 18 an outlier or no?

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No because 21 is close to it.

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3 years ago

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I answered it but I just need someone to answer just to make sure mine are right

Artemon [7]

<h2>The missing measures of the angles are:</h2>

$m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

<u>Given</u>:

$m\angle Z = 138^{\circ}$

<em><u>Note the following:</u></em>

An equilateral triangle has all its three angles equal to each other. Each angle = $60^{\circ}$ .

This implies that, since $\triangle WXY$ is equilateral, therefore, $m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}$

Base angles of an isosceles triangle are congruent to each other.

This implies that, since $\triangle WZY$ is isosceles, therefore, $m\angle 3 = \angle 5$

Applying the above stated, let's find the measure of each angle:

Find $m\angle 1$

$m\angle 1 = 60^{\circ}$ (an angle in an equilateral triangle equals 60 degrees)

Find $m\angle 2$

$m\angle 2 = 60 - m \angle 3$

$m\angle 2 = 60 -\frac{1}{2}(180 - 138)$ $(Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}$

Find $m\angle 3$ and $m\angle 5$ (base angles of isosceles triangle WZY)

$m\angle 3 = \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 3 = \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}$

$m\angle3 = m\angle 5$ (base angles of isosceles triangle are congruent)

Therefore,

$m\angle5 = 21^{\circ}$

Find $m\angle 4$

$m\angle 4 = 60 - m\angle 5$

Substitute

$m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}$

The missing measures of the angles are:

$m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

Learn more here:

brainly.com/question/2944195

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2 years ago

Help please need it by tonight

inysia [295]

Answer:

1) (n+5)(n-1)

2) (n-4)(n+3)

3) (v-4)(v-1)

4) (p-4)(p+2)

5)(7x-10)(x+1)

6)(7n-1)(n-9)

Step-by-step explanation:

1) Factors of -5 that add up to 4

2) Factors of --12 that add up to -1

3) Factors of 4 that add up to -5

4) Factors of -5 that add up to 4

5) 7 $x^{2}$ -3x-10

7 $x^{2}$ +7x-10x-10

7x(x+1)-10(x+1)

(7x-10)(x+1)

6)7 $n^{2}$ -64n+9

7 $n^{2}$ -63n-n+9

7n(n-9)-(n-9)

(7n-1)(n-9)

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2 years ago