Y = 3x y = -x + 4 write the question in coordinate form

An accounting firm has recently recruited six graduates: three men and three women. Three of the graduates are to be selected at

solong [7]

Answer:

a) The probability tree is constructed below

b) the probability that at least two women will be selected is 0.500

Step-by-step explanation:

Given the data in the question;

a) The probability tree is as follows;

3 men, 3 women

↓

_______________________|________________________

↓ ↓ ↓ ↓

3 men 2 men 1 man 0 men

0 women 1 woman 2 woman 3 women

b) the probability that at least two women will be selected

p( at least two women would be selected) = P( there are 2 women out of 3 ) + P( there 3 women out of 3

so

p( at least two women would be selected) = C

³C₂ × ³C₁ / ⁶C₃ + ³C₃³C₀ / ⁶C₃

= 3!/(2!(3-2)!) × 3!/(1!(3-1)!) / 6!/(3!(6-3)!) + 3!/(3!(3-3)!) × 3!/(0!(3-0)!) / 6!/3!(6-3)!)

= 3 × 3 / 20 + 1 × 1 / 20

= 9/20 + 1/20

= 0.45 + 0.05

p( at least two women would be selected) = 0.500

Therefore, the probability that at least two women will be selected is 0.500

6 0

2 years ago

Consider the line y =

posledela

Answer:

y= what? Whats the first equation

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

In a volleyball game, a player on one team spikes the ball over the net when the ball is 10 feet above the court. The spike driv

Fynjy0 [20]

Answer:

4.75 seconds

Step-by-step explanation:

Initial height of the ball from the ground = 10 feet

Upward initial velocity given = 55 feet per second

Value of g ( acceleration due to gravity) = 32.2 feet per s²

Motion of the ball:

The ball first goes vertically upwards, gravity decelerates the body and it momentarily comes to rest at a point in its upward trajectory, which is the point of maximum height. From this point, to the ground, the ball behaves as a freely dropped body.

Till the ball reaches its maximum height:

u = + 55

v = 0 ( final velocity is zero)

a = - 32.2 (since it is deceleration)

we know that v = u + at

⇒ 0 = 55 - 32.2t

⇒ t = 1.7 s

Also , we have s = ut + (1/2)at²

Here, s is the maximum height from the point where ball is thrown

So, s = 55(1.7) - (0.5)(32.2)(1.7)(1.7)

⇒ s = 140 feet

So at a height of 140 feet + 10 feet (initial height) = 150 feet, the ball acts as a freely dropped body.

Here, u = 0

a = +32.2

s= 150

s = ut + (1/2)at²

⇒ 150 = 0.5 ( 32.2) (t²)

⇒ t² = 300/32.2 = 9.31

⇒ t = 3.05 sec

So total time = 1.7 + 3.05 = 4.75 seconds

8 0

3 years ago

Please answer this question now

larisa [96]

Answer:

1471.15

Step-by-step explanation:

4 0

2 years ago

Please find which quadratic equation matches the graph with work attached

lesya [120]

Answer:

C

Step-by-step explanation:

Firstly, we know that the function must be negative due to its shape. This means that the answer cannot be B

Next we can use the equation $x=\frac{-b}{2a}$ that is used in order to find the vertex of the parabola.

A)

$f(x)=-x^2+6x+7\\a=-1,b=6,c=7\\\\x=\frac{-6}{-2} \\x=3$

As the vertex is at x=3 on the graph, this one could be a contender.

C)

$f(x)=-x^2+6x-7\\a=-1,b=6, c=-7\\\\x=\frac{-6}{-2} \\\\x=3$

This also could be the equation

D)

$f(x)=-x^2-6x-7\\\\a=-1, b=-6, c=-7\\\\x=\frac{6}{-2} \\\\x=-3$

This rules option D out.

For this last step, we can look at where the zeroes would be for each equation. (These values are irrational, so we cannot look at specific number)

A)

$f(x)=-(x^2-6x-7)$

As this equation has a negative value for c, this means that one zero must be positive and the other must be negative.

This means that option A can be ruled out

C)

$f(x)=-(x^2-6x+7)$

As this equation has a positive value for c, this means that both of the zeroes must be positive. This means that it is the only one that fits all of the criteria.

7 0

2 years ago