$80-$2= $78 is the number less than $80, since the pens cost $2
78/2= 39 pens is the greatest number of pens sold
hope this helps
The net change between the given values of the variable is 6a - 6
<h3>How to determine the net change between the given values of the variable?</h3>
The given parameters are
g(x) = 6x
Where
x = 1 and x =a
Calculate g(1) and g(a)
So, we have
g(1) = 6 * 1
g(1) = 6
g(a) = 6 * a
g(a) = 6a
The net change between the given values of the variable is
Change = g(a) - g(1)
So, we have
Change = 6a - 6
Hence, the net change between the given values of the variable is 6a - 6
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Answer:
5
Step-by-step explanation:
[math]
U_{n} = 5n - 2 \\
Common Difference = U_{n+1} - U_{n} \\
= [5(n + 1) - 2] - [5n - 2] = [5n + 5 - 2] - [5n - 2]\\
= 5n + 5 - 2 - 5n + 2\\
= 5
[/math]
Answer:
The enrollment after 5 years is 10,724
Step-by-step explanation:
Generally, we can have the depreciation formula written as follows;
A = P(1 - r)^t
A is the number of enrollment in after a certain number of years t
P is the initial population which is 13,500
r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045
t = 5 years
Substituting these values, we have it that;
A = 13,500(1-0.045)^5
A = 10,723.84
You can let the sides be a and b. You can then use the Law of Sines to create an equation relating the two sides and the angles opposite them, and finally isolate a/b.
