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3 years ago

A turtle can walk 1/12 of a kilometer in an hour. The turtle is 1/5 of a kilometer away from a pond.

Mathematics

1 answer:

NISA [10]3 years ago

6 0

Answer:

2 2/5 hour

Step-by-step explanation:

Complete Question

A turtle can walk 1/12 of a kilometer in an hour. The turtle is 1/5 of a kilometer away from a pond.At this speed how long will it take the turtle to reach the pond?

From the above question:

1/12 km = 1 hour

1/5 km = x hour

Cross Multiply

1/12 km × x hour = 1/5 km × 1 hour

x hour = 1/5 km × 1 hour/1/12 km

x hour = 1/5 km ÷ 1/12 km

x hour = 1/5 × 12 hour

x hour = 12/5 hour

x hour = 2 2/5 hour

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Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago

Take LCM ald then do in full processplease help me

Marina86 [1]

Answer:a) L.C.M OF 2,3,5 is 30

THEREFORE=60/30+15/30÷10/30-6/30

=60/30+15/30×30/10-6/30(DMAS)

=60/30+3/2-6/30

=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.

=105/30-6/30

=105-6/30

=99/30

=33/10

b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3

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Step-by-step explanation:

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Check the picture below.

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