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3 years ago

15

Mr. Lee bought rock to landscape around his house. He paid $190.72 for 8 tons of rock. How much did each ton cost?

1 answer:

frez [133]3 years ago

6 0

Answer:

the correct answer I's 23.84

Step-by-step explanation:

I dividedc190.72 by 8

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Please help with at least one question.

Cloud [144]

Okay, first off negative is well negative and since there is no other negatives, -5/7 is least (making it go first). Second, what is smaller 3/5 or 2/9, remember that the bigger the denominator the smaller the piece.

[/] [/] [/] [] [] = 3/5

[/] [/] [] [] [] [] [] [] [] 2/9

At the end it should be -5/7, 2/9 , 3/5. This method can go the same for problems like these...Hope it helps!

7 0

2 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

3 years ago

How do u simplify 3/30

sukhopar [10]

$\bf \cfrac{3}{30}\implies \cfrac{3\cdot 1}{3\cdot 10}\implies \cfrac{3}{3}\cdot \cfrac{1}{10}\implies 1\cdot \cfrac{1}{10}\implies \cfrac{1}{10}$

8 0

3 years ago

What is the value of a when we rewrite 8^x as a^-x/9

Andre45 [30]

Answer:

$a = \frac{1}{134217728}$

Step-by-step explanation:

Given

$8^x = a^{-x/9}$

Required

Find a

Take log of both sides

$log(8^x) = log(a^{-x/9})$

Apply law of logarithm

$x\ log(8) = (-x/9) log(a)$

Divide both sides by a

$log(8) = -\frac{1}{9} log(a)$

Multiply both sides by -9

$-9\ log(8) = log(a)$

Apply law of logarithm

$log(8^{-9}) = log(a)$

Cancel out log

$8^{-9} = a$

Rewrite as:

$a = 8^{-9}$

Apply law of indices

$a = \frac{1}{8^9}$

$a = \frac{1}{134217728}$

4 0

3 years ago

Write two equivalent expression with these numbers 14,16,11

eduard

Answer:

14+16+11=41

11+14+16=41

Step-by-step explanation:

3 0

2 years ago