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3 years ago

The mass of an electron is

Mathematics

1 answer:

alekssr [168]3 years ago

4 0

Remark

The electron has a mass that is roughly 1/1800 the size of either the proton or the electron. In comparison the electron's mass is very small comparred to the other 2.

Solution

A is totally wrong. A part of an atom can't weight the same as the atom.

B is totally wrong as well. See the remark above.

D is wrong. See the remark above

C is the answer. It's mass is quite small compared to the other 2.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v

olga_2 [115]

We are given

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now, we can plug point (-5,5,2)

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$f_z=3(2)^2=12$

so, gradient will be

$gradf=(50,-25,12)$

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

$|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}$

$|v|=\sqrt{29}$

now, we can find unit vector

$v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

now, we can find dot product to find direction of the vector

$dir=(gradf) \cdot (v')$

now, we can plug values

$dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })$

$dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })$

$dir=-\frac{248\sqrt{29}}{29}$ .............Answer

7 0

4 years ago

Read 2 more answers