Answer with Step-by-step explanation:
(3.a) GCD(343,550), LCM(343, 550).
343=7×7×7
550=5×5×2×11
GCD(343,550)=1
LCM(343,550)=7×7×7×5×5×2×11=188650
(3.b) GCD(89, 110), LCM(89, 110).
89=1×89
110=5×2×11
GCD(89, 110)=1
LCM(89, 110)=89×5×2×11=9790
(3.c) GCD(870, 222), LCM(870, 222).
870=2×3×5×29
222=2×3×37
GCD(870, 222)=2×3=6
LCM(870, 222)=2×3×5×29×37=32190
In the first one it would be (21-8)-6=7.
and in the second one it would be 21-(8-6)=19
Answer:
Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.
Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity
Step-by-step explanation:
Given that the vector b = (-2, -1) can be written as follows;
b = -2·i - j, we have;
= √((-2)² + (-1)²) = √5
Therefore, we have;
The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)
Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2
The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))
Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.
C=pid
Since d=9m and pi=3.142, C=3.142*9m=28.278
Rounded to 1 decimal point =28.3