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hammer [34]
3 years ago
12

xplain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that the

standard deviation has over the interquartile​ range? Choose the correct answer below. A. The interquartile range is preferred when the data are bell shaped. An advantage of the standard deviation is that it is resistant to extreme values. B. The interquartile range is preferred when the data are bell shaped. An advantage of the standard deviation is that it increases as the dispersion of the data increases. C. The interquartile range is preferred when the data are not skewed or no have outliers. An advantage of the standard deviation is that it uses all the observations in its computation. D. The interquartile range is preferred when the data are skewed or have outliers. An advantage of the standard deviation is that it uses all the observations in its computation. E. The interquartile range is preferred when the distribution is symmetric. An advantage of the standard deviation is that it increases as the dispersion of the data increases. F. The interquartile range is preferred when the distribution is symmetric. An advantage of the standard deviation is that it is resistant to extreme values.
Mathematics
1 answer:
uranmaximum [27]3 years ago
8 0

Answer: The interquartile range is preferred when the data are skewed or have outliers. An advantage of the standard deviation is that it uses all the observations in its computation.

Step-by-step explanation:

The interquartile range are resistant to outliers and can be used for data having glaring outliers.

Outliers are values that are too far away from the central value.

Interquartile range is a better option than standard deviation when there are a few extreme values and the distribution is skwed.

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dybincka [34]

Answer:

  \log{\dfrac{3\sqrt{x}(x^3+4)}{2}}

Step-by-step explanation:

\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}

__

The applicable rules of logarithms are ...

  log(ab) = log(a) +log(b)

  log(a/b) = log(a) -log(b)

  log(a^b) = b·log(a)

3 0
3 years ago
For a school fundraiser mai will make school spirit bracelets. She will order bead wiring and alphabet beads to create the schoo
Andreas93 [3]

Answer:

235 bracelets

Step-by-step explanation:

Mai must spend $250 on wire and $5.30 per bracelet beads. Mai creates the expression.

We are given the equation:

5.3n+ 250 to represent the cost of making n bracelets.

The maximum number of bracelets Mai can make with a budget of $1500 Is calculated as:

$1500 = 5.3n+ 250

Collect like terms

1500 - 250 = 5.3n

1250 = 5.3n

n = 1250/5.3

n = 235.8490566 bracelets.

Bracelets are created as whole numbers and they can't be in decimal form.

Therefore, the maximum number of bracelets Mai can make with a budget of $1500 is 235 bracelets.

6 0
3 years ago
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tigry1 [53]

Answer:

$43.35 (I believe)

Step-by-step explanation:

I tried to find the price to fill up 1 gallon by dividing the $30.60 by 12. 30.6/12 = 2.55 and then I multiplied $2.55 by 17 and got $43.35

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Step-by-step explanation:

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3 years ago
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