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3 years ago

7

Solve the following dividend problem.alameda tent company has 75,000 shares of stock outstanding. what total dividend declaratio

n would be necessary for the dividend per share to be $2.00.

2 answers:

butalik [34]3 years ago

5 0

75,000×2=150,000
...............

Otrada [13]3 years ago

4 0

Answer:

150.000

Step-by-step explanation:

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2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

(c) $P(X > 980) = 0.00001\\\\$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

3 years ago

Carlos is analyzing the results of an experiment on two groups of mice in which he compared the difference in their weight gain

Arlecino [84]

Given:difference in the mean weight gain is 0.60 gramsstandard deviation of the difference in sample mean is 0.305
68% confidence interval for the population mean difference is a) 0.305
0.60 + 1 * 0.3050.60 + 0.305 = 0.9050.60 - 0.305 = 0.295
95% confidence interval for the population mean difference is c) 0.61
0.60 + 2 * 0.3050.60 + 0.61 = 1.210.60 - 0.61 = -0.01

3 0

3 years ago

Based on the diagram select all that apply.

Sveta_85 [38]

Answer:

E

Step-by-step explanation:

I just think so. Maybe it's right

4 0

2 years ago

Please help need it quick will give brainliest thanks

Norma-Jean [14]

Use the Pythagorean theorem:

$x^2+8^2=11^2\\\\x^2+64=121\ \ \ |-64\\\\x^2=57\to x=\sqrt{57}\\\\x\approx7.5$

Answer: C. 7.5

8 0

2 years ago

Read 2 more answers

Find the value of x when the triangle has 9 and 3

DENIUS [597]

Answer:

H²=h²+b²

H²=9²+3²

H²=81+9

H²=90

H=

$\sqrt{90}$

5 0

2 years ago