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givi [52]
3 years ago
7

Formula area of the square​

Mathematics
1 answer:
Misha Larkins [42]3 years ago
4 0
A= l * W (area = length times width)
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34​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
finlep [7]

Answer:

a) There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

b) There is a 71.62% probability that more than two students use credit cards because of the rewards program.

c) There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this problem by the binomial distribution.

Binomial probability

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 student are sampled, so n = 10

34% of college students say they use credit cards because of the rewards program, so \pi = 0.34

(a) exactly​ two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

There is a 18.73% probability that exactly two students use credit cards because of the rewards program.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.34)^{0}.(0.66)^{10} = 0.0157

P(X = 1) = C_{10,1}.(0.34)^{1}.(0.66)^{9} = 0.0808

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0157 + 0.0808 + 0.1873 = 0.2838

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.2838 = 0.7162

There is a 71.62% probability that more than two students use credit cards because of the rewards program.

(c) between two and five inclusive

This is:

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.34)^{2}.(0.66)^{8} = 0.1873

P(X = 3) = C_{10,3}.(0.34)^{3}.(0.66)^{7} = 0.2573

P(X = 4) = C_{10,4}.(0.34)^{4}.(0.66)^{6} = 0.2320

P(X = 5) = C_{10,5}.(0.34)^{5}.(0.66)^{5} = 0.1434

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1873 + 0.2573 + 0.2320 + 0.1434 = 0.82

There is a 82% probability that between two and five students, inclusive, use credit cards because of the rewards program.

6 0
3 years ago
What is the factor of x^2 -9x +18
Rashid [163]
X^2 - 9x + 18
factors of 18: 1*18, 2*9, 3*6,
the sums of the factors: 19, 11, 9
the positive 18 tells us both factors have the same sign, the negative 9 tells us they are both negative
(x - 3)(x - 6)
5 0
3 years ago
This is a better photo I can’t figure this one out. Any help?
natali 33 [55]

Answer:

the answer is 4

Step-by-step explanation:

because i did it on desmos that is a graphic calculator

3 0
3 years ago
Read 2 more answers
GIVING THE BRAINLIEST ANSWER
Ahat [919]

Answer:

(6,3)

Step-by-step explanation:

y=2/3 x - 1

y=-1/2 x + 6

Since both equations are equal to y, we can set them equal

2/3 x - 1 =-1/2 x + 6

We have fractions, so I will multiply by 6 to clear the fractions

6(2/3 x - 1) =(-1/2 x + 6)6

Distribute

4x -6 = -3x +36

Add 3x to each side

4x+3x -6 = -3x+3x +36

7x -6 = 36

Add 6 to each side

7x-6+6 = 36+6

7x = 42

Divide each side by 7

7x/7 = 42/7

x =6

Now we need to find y

y =2/3x -1

y = 2/3(6) -1

y = 4-1

y=3

(6,3)

5 0
3 years ago
What’s the simplified expression?
Katyanochek1 [597]

Answer:

(-3/4)^{10}

Step-by-step explanation:

using the rule of exponents

• (a^m)^{n} = a^{mn}

((-3/4)^5)^{2} = (-3/4)^{10}


7 0
3 years ago
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