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Novosadov [1.4K]
3 years ago
12

Solve the following and graph the solutions:

Mathematics
1 answer:
Oksanka [162]3 years ago
4 0
<h2>Solving Compound Inequalities</h2><h3>Answer:</h3>

The third Choice

x > 1 \text{ or } x < -1

<em>Please</em><em> refer</em><em> to</em><em> the</em><em> attached</em><em> image</em><em> </em><em>for</em><em> the</em><em> </em><em>graph</em>

<h3>Step-by-step explanation:</h3>

Given:

2x +1 > 3 \text{ or } 2x -1 < -3

Let's solve for the 2x +1 > 3 part of the Compound Inequality first.

2x +1 > 3 \\ 2x > 3 -1 \\ 2x > 2 \\ x > \frac{2}{2} \\ x > 1

Now, let's solve 2x -1 < -3:

2x -1 < -3 \\ 2x < -3 +1 \\ 2x < -2 \\ x < \frac{-2}{2} \\ x < -1

We can now rewrite our Compound Inequality as x > 1 \text{ or } x < -1

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Solve (16×^3-3×^2+43×-5)÷(×^2-2)
Oksana_A [137]

Answer:

3872/(x^2 - 2)

Step-by-step explanation:

Simplify the following:

(16^3 - 3^2 - 5×43)/(x^2 - 2)

3^2 = 9:

(16^3 - 9 - 5×43)/(x^2 - 2)

16^3 = 16×16^2:

(16×16^2 - 9 - 5×43)/(x^2 - 2)

| 1 | 6

× | 1 | 6

| 9 | 6

1 | 6 | 0

2 | 5 | 6:

(16×256 - 9 - 5×43)/(x^2 - 2)

16×256 = 4096:

(4096 - 9 - 5×43)/(x^2 - 2)

43 (-5) = -215:

(4096 - 9 + -215)/(x^2 - 2)

4096 - 9 - 215 = 3872:

Answer: 3872/(x^2 - 2)

7 0
3 years ago
Simplify: -1/2(6n+4) +2n - 5
Maurinko [17]

Answer:

Step-by-step explanation:

\frac{-1}{2}(6n+4)+2n-5 \\\\\frac{-1}{2}2(3n+2)+2n-5\\ -(3n+2)+2n-5\\-3n-2+2n-5\\-n-7

5 0
3 years ago
I have 30 ones, 82 thousand, 60tens and 100 hundreds
Neporo4naja [7]
That creates the number 82,190
6 0
3 years ago
william is thinking of two numbers both numbers are square numbers greater than 1 the sum of numbers is 100 write down two numbe
zheka24 [161]

Answer:

Step-by-step explanation:

At first,

Let start writing the squares of number 0 to 10,

0²=0

1²=1

2²=4

3²=9

4²=16

5²=25

6²=36

7²=49

8²=64

9²=81

10²=100

Now,

According to your question,

  1. The two numbers should be square numbers
  2. They should be greater than 1.
  3. Their sum should be 100.

Hence, your given conditions matches with the numbers 64 and 36.

Therefore, the numbers are 64 and 36.

  • 64 and 36 are greater than 1.
  • 64 is a square of 8 and 36 is the square of 6.
  • 64+36=100
3 0
3 years ago
Solve for x: 3 &lt; X + 3 &lt; 6
larisa86 [58]

Answer:

0<x<6

I think this is right, hope this helps!

4 0
3 years ago
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