
The mistake is in Step 1. The solver should have also squared
when squaring the other side of the equation.
<h3>Correctly solving</h3>

So make and angle with the measure of 45 degrees. And then label it DOG. It doesn't matter where you start labeling as long as O is your midpoint. :)
Answer:
Area of circle A =113.14 mm²
Area of circle b = 314.29 mm²
Area of circle C = 452.57 mm²
Area of circle A = 254.57 mm²
2.25 times
Step-by-step explanation:
Area of a circle = nr²
where n = 22/7
r = radius
Circle A's radius = 6mm
Circle B's radius = 6mm + 4mm = 10mm
Circle C's radius = 10mm + 2mm = 12mm
Circle D's radius = 12mm - 3mm = 9mm
Area of circle A = (22/7) x 6² = 113.14 mm²
Area of circle b = (22/7) x 10² = 314.29 mm²
Area of circle C = (22/7) x 12² = 452.57 mm²
Area of circle A = (22/7) x 9² = 254.57 mm²
Number of times the area of circle D is greater than that circle A = Area of circle D / Area of circle A
254.57 mm² / 113.14 mm² = 2.25 times
3(2a-5) = 12-7a
6a-15=12-7a
6a+7a=12+15
13a= 27
27=3c-3(6-2c)
27=3c-18+6c
27+18=3c+6c
45=9c
C=45/9
C=5
6c-8-2c=-16
6c-2c=-16+8
4c=-8
C=-8/4
C=-2
false
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