3 years ago

Which equation can be used to find one-tenth of 119.9

Mathematics

1 answer:

mel-nik [20]3 years ago

3 0

To find one tenth of 119.9 just divide 119.9 by 10

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Simplify (4-2)^5 A. 4^10 B. 4^3 C. 1/4^3 D. 1/4^10

zvonat [6]

Your answer is A because 2x5 equal 10

5 0

3 years ago

How many hours would someone earns 7.50 per hour have to work to earn $116.25

SCORPION-xisa [38]

Let h = amount of hours

$7.5h=116.25$

Since they earn $7.50 per hour, we can multiply that by an unknown amount of hours to get $116.25. Let's solve:

$7.5h=116.25$

Divide both sides by 7.5 to isolate the h, amount of hours.

$\frac{7.5h}{7.5}=\frac{116.25}{7.5}$

Simplify.

$h=15.5$

In conclusion, someone would have to work 15.5 hours to earn $116.25 if they earn $7.50 per hour.

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3 years ago

Name the sides of the angle and classify the angle according to its measure

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

The answer is b.

Hope this helped!

3 0

3 years ago

Write an equation in point-slope form for the line that satisfies the given set slope of 4/5, passes through (10,-30

hodyreva [135]

Answer:

y + 30 = 4/5(x - 10)

Step-by-step explanation:

Given the slope, 4/5, and point (10, -30):

We can plug these values into the point-slope form:

y - y1 = m(x - x1)

Let (x1, y1) = (10, -30)

and m = 4/5

y - (-30) = 4/5(x - 10)

y + 30 = 4/5(x - 10)

Therefore, the point-slope form is y + 30 = 4/5(x - 10)

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali

Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

$\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}$

rewrite the root

$\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}$

then cancel the terms that are cubes and bring them out of the root

$\sqrt[3]{80}=2\sqrt[3]{10}$

7 0

1 year ago