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amid [387]
3 years ago
5

Someone pls help me

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0
3 and proportional
Nesterboy [21]3 years ago
5 0
3 and yes it is ​‎.
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A train was traveling at a constant speed. The table below shows the distance, in miles, the train traveled the first 4 hours, W
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Answer:

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Step-by-step explanation:

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2 years ago
Verify the pythagorean identity 1 + c o t ^2 θ = c s c ^2 θ
Grace [21]

Answer: The identity is verified. See the explanation.

Step-by-step explanation:

You must keep on mind the following identities:

csc\theta=\frac{cos\theta}{sin\theta}\\\\csc\theta=\frac{1}{sin\theta}\\\\sin^2\theta+cos^2\theta=1

Therefore, by substitution, you can rewrite the identity as shown below:

1+cot^2\theta=csc^2\theta\\\\1+\frac{cos^2\theta}{sin^2\theta}=csc^2\theta

Simpliying, you obtain:

\frac{sin^2\theta+cos^2\theta}{sin^2\theta}=csc^2\theta\\\\\frac{1}{sin^2\theta}=csc^2\theta\\\\csc^2\theta=csc^2\theta

The identity is verified.

6 0
3 years ago
Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0
2 years ago
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Find x and y, given that KL and line MN are parallel. Show all work
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\dfrac{|MN|}{|NJ|}=\dfrac{|KL|}{|LJ|}\\\\\dfrac{22}{12+8}=\dfrac{y}{8}\\\\\dfrac{22}{20}=\dfrac{y}{8}\ \ \ |cross\ multiply\\\\20y=22\cdot8\\\\20y=176\ \ \ |:20\\\\\boxed{y=8.8}

\dfrac{|MK|}{|KJ|}=\dfrac{|NL|}{|LJ|}\\\\\dfrac{x-2}{5}=\dfrac{12}{8}\ \ \ \ |cross\ multiply\\\\8(x-2)=5\cdot12\\\\8x-16=60\ \ \ |+16\\\\8x=76\ \ \ |:8\\\\\boxed{x=9.5}
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2 years ago
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4. two lines are perpendicular when
Gre4nikov [31]

c c a a are the right answers just took it

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3 years ago
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