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3 years ago

Someone pls help me

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

8 0

3 and proportional

Nesterboy [21]3 years ago

5 0

3 and yes it is ‎.

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A train was traveling at a constant speed. The table below shows the distance, in miles, the train traveled the first 4 hours, W

myrzilka [38]

Answer:

need please

Step-by-step explanation:

it's for today please help me

5 0

2 years ago

Verify the pythagorean identity 1 + c o t ^2 θ = c s c ^2 θ

Grace [21]

Answer: The identity is verified. See the explanation.

Step-by-step explanation:

You must keep on mind the following identities:

$csc\theta=\frac{cos\theta}{sin\theta}\\\\csc\theta=\frac{1}{sin\theta}\\\\sin^2\theta+cos^2\theta=1$

Therefore, by substitution, you can rewrite the identity as shown below:

$1+cot^2\theta=csc^2\theta\\\\1+\frac{cos^2\theta}{sin^2\theta}=csc^2\theta$

Simpliying, you obtain:

$\frac{sin^2\theta+cos^2\theta}{sin^2\theta}=csc^2\theta\\\\\frac{1}{sin^2\theta}=csc^2\theta\\\\csc^2\theta=csc^2\theta$

The identity is verified.

6 0

3 years ago

Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th

VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

$f(x)=16-\frac{x^2}{3}$

To find $f(-64)$ , we substitute $x=-64$ into the function.

$f(-64)=16-\frac{(-64)^2}{3}$

$f(-64)=16-\frac{4096}{3}$

$f(-64)=-\frac{4048}{3}$

To find $f(64)$ , we substitute $x=64$ into the function.

$f(64)=16-\frac{(64)^2}{3}$

$f(64)=16-\frac{4096}{3}$

$f(64)=-\frac{4048}{3}$

To find $f'(c)$ , we must first find $f'(x)$ .

$f'(x)=-\frac{2x}{3}$

This implies that;

$f'(c)=-\frac{2c}{3}$

$f'(c)=0$

$\Rightarrow -\frac{2c}{3}=0$

$\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}$

$c=0$

For this function to satisfy the Rolle's Theorem;

It must be continuous on $[-64,64]$ .

It must be differentiable on $(-64,64)$ .

and

$f(-64)=f(64)$ .

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0

2 years ago

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Find x and y, given that KL and line MN are parallel. Show all work

Setler [38]

$\dfrac{|MN|}{|NJ|}=\dfrac{|KL|}{|LJ|}\\\\\dfrac{22}{12+8}=\dfrac{y}{8}\\\\\dfrac{22}{20}=\dfrac{y}{8}\ \ \ |cross\ multiply\\\\20y=22\cdot8\\\\20y=176\ \ \ |:20\\\\\boxed{y=8.8}$

$\dfrac{|MK|}{|KJ|}=\dfrac{|NL|}{|LJ|}\\\\\dfrac{x-2}{5}=\dfrac{12}{8}\ \ \ \ |cross\ multiply\\\\8(x-2)=5\cdot12\\\\8x-16=60\ \ \ |+16\\\\8x=76\ \ \ |:8\\\\\boxed{x=9.5}$

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2 years ago

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4. two lines are perpendicular when

Gre4nikov [31]

c c a a are the right answers just took it

8 0

3 years ago

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